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Find m < (angle) EBD if m<ABE =12n-8 andm<ABD = 22n-11

its not a triangle either so dont go thinking it is lol...looks like this

..............\-A....|-E.../ - D
................\.....|..../
..................\...|.../
....................\.|./
......................\/ - B
........................\
..........................\
............................\
..............................\ - C

ONLY DO THIS IF YOU ACTUALLY KNOW HOW TO!! plz

k fixed it...it was all messed up lol

I know Geometry!

well how do i work it then?

i need to show my work....so yeah and none of the formulas she gave me even help threw the damn answer....gah!!

12n-8+22n-11=90

Line AB Bisects ABD, so ABE = EBD. In other words, plug that answer into 12n-8, and you got it.

12n-8+22n-11=90
34n-8-11=90
34n-19=90
....+19..+19
34n =109
34..34

n= 3.21

12(3.21) -8
38.52 - 8
30.52

the problem is....the back of the book says the answer is 22

k.....now this is in the offtopic forum....heres another problem lol...the meausre of an angle is 44 more then the measure of its supplement. find the measures of the angles.....

wtf ^ ?

Originally posted by crazy_shadow
k.....now this is in the offtopic forum....heres another problem lol...the meausre of an angle is 44 more then the measure of its supplement. find the measures of the angles.....

wtf ^ ?
math sucks

I don't get that drawing...so I can't help

i got 30.25

u know what imma just say screw those 5 problems and ask the teacher tomarrow mornin cuz ive been workin on them 4ever and its just a waste of time...the only question im surprised i got the answer to was

"find the measures of two complementary angles, <A and <B, if m<A=7x + 4 and m<B=4x + 9"

just had to put it..i was proud of myself for gettin the answer....

Originally posted by crazy_shadow
k.....now this is in the offtopic forum....heres another problem lol...the meausre of an angle is 44 more then the measure of its supplement. find the measures of the angles.....

wtf ^ ?

Let x be the supplement.....
Let x + 44 be the angle......

180 (amount of degrees in supplementary angles)= 2x + 44
180-44=2x
x=68

So the supplement angle is 68 and the other angle is 68+44=112.

Right answer?

Originally posted by crazy_shadow
u know what imma just say screw those 5 problems and ask the teacher tomarrow mornin cuz ive been workin on them 4ever and its just a waste of time...the only question im surprised i got the answer to was

"find the measures of two complementary angles, <A and <B, if m<A=7x + 4 and m<B=4x + 9"

just had to put it..i was proud of myself for gettin the answer....


(7x + 4) + (4x +9) = 90
11x = 90 - 13
11x = 77
x= 7


Therefore (7x+4)= 53 and (4x + 9)= 37?

I don't get what the m means

I didn't know Silver was so smart.

Oh gee thanks

Hey, no problem.

Originally posted by Neo_Version 7
I didn't know Silver was so smart.
I think she got something 'round 90 average. Or 94.

she showed me how to do it and she said i dont have to do it since it was so hard for everyone lol

Find m < (angle) EBD if m<ABE =12n-8 and m<ABD = 22n-11

since ABE is congruent to EBD that means they are the same so..

m<EBD = m<1 m<ABE = m<2 m<ABD = m<3
so m<1 + m<2 = m<3
since m<ABE = 12n - 8 ......

2 (12n - 8) = 22n - 11
24n - 16 = 22n - 11
......+11 = ......+11
24n - 5 = 22n
-24n........-24n
-5 = 2n
(divde by 2)
-2.5 = n which turns into 2.5 = n

then you can do this.... 12n-8 which is 12(2.5)-8 and the answer is 22

Originally posted by DarkC
I think she got something 'round 90 average. Or 94.

94

Originally posted by DarkC
I think she got something 'round 90 average. Or 94. or u can jus read wat i just said