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Self-explanatory.

E.g. you ask someone:

Jack Sparrow had 1200 galleons. If Jack Sparrow sold 500 galleons to Davy Jones. But Davy Jones then destroyed another 500 galleons owned by Jack Sparrow.

How many galleons does Sparrow have left?

Please answer.

I don't really see this catching on. hmm

But interesting idea.

retturnnerr + 'New topic' button = the most retarded threads on KMC glare

Retarded?!

I can sight yourself dumbfounded, not trying to understand the logic.

What I'm trying to do is to let you state a hard mathematical problem and let others answer it.

Get it?

Math is not fun.


edit: Why the **** would Jack sell galleons?

1+2=4

Originally posted by retturnnerr
Retarded?!

I can sight yourself dumbfounded, not trying to understand the logic.

What I'm trying to do is to let you state a hard mathematical problem and let others answer it.

Get it?

But the logic of this thread sucks sly

yeah we aint exactly math people here
except ABS

200. I think.

I mean I'm a complete idiot at maths but I think I'm still right.

Change 1200 into 12, to simplify it. 12 - 5 = 7. Then 7 - 5 = 2.

Unsimplify it back into hundreds and there we have 200.

the derivative of X^2 is 2x while the integral of X^2 is 1/3x^3

my head hurts

this isn't my home

of couse

This is thread will die quickly.

People hate math.

Originally posted by Mr. Bacon
1+2=4

for large values of 1!

Originally posted by Mr. Bacon
the derivative of X^2 is 2x while the integral of X^2 is 1/3x^3

Actually the integral is (1/3)x^3 + C

Originally posted by AbnormalButSane
Actually the integral is (1/3)x^3 + C

The constant....that's where they get you.

Every time!

somehow i was able to pass math with a B
and luckily i didnt have to take it last year caw00t

1200 - 500 - 500 = 200.


This shit is boring, honestly.

Originally posted by AbnormalButSane
Actually the integral is (1/3)x^3 + C
yes, yes it is, stupid C. mmm

Originally posted by Mr. Bacon
yes, yes it is, stupid C. mmm
You were close though. petpet

I did a problem this morning:

k(del^2 u/ del x^2)=(del u/del t)
where 0<x<L, t>0

with the conditions
u(0,t)=0, u(L,t)=0, t>0
u(x,0)=f(x), 0<x<L

Hint: Assume u(x,t) = X(x)T(t)


God, I love DE. doped

Originally posted by AbnormalButSane
You were close though. petpet

I did a problem this morning:

k(del^2 u/ del x^2)=(del u/del t)
where 0<x<L, t>0

with the conditions
u(0,t)=0, u(L,t)=0, t>0
u(x,0)=f(x), 0<x<L

Hint: Assume u(x,t) = X(x)T(t)


God, I love DE. doped
its summer, I got a B+ in the class and i skipped halfof them, cant complain

and yea, **** that

Originally posted by JacopeX
This is thread will die quickly.

People hate math.

But people love spam

Originally posted by retturnnerr
Self-explanatory.

E.g. you ask someone:

Jack Sparrow had 1200 galleons. If Jack Sparrow sold 500 galleons to Davy Jones. But Davy Jones then destroyed another 500 galleons owned by Jack Sparrow.

How many galleons does Sparrow have left?


1200 - 500 = 700
700 - 500 = 200

ANSWER 200

1+1= WINDOWS

Dominic jump roped. He jump roped 450 times.


He weighs exactly 100 KG. (I just weighed myself and It's almost exactly 100Kg.)

Dominic averages .25 meters on the maximum height of each jump.

Each jump also expends an extra .2 joules by lifting both feet up, unnecessarily, as humans tend to do that when jump roping. (If we want to get even more accurate, I could give an average distance the feet are raised during the jump, to actually give people the chance to calculate exactly how many joules are used to pull those feet up...it would require the weight of the feet, distance between knee and bottom of the foot, weight distribution of the leg, i.e. the top part weighs more, but the bottom part is the furthest out. etc. But that would make it far too complicated.)


Likewise, it requires Dominic .08 joules to spin the rope one complete turn, on average.

Calculate the number of joules required for Dominic to complete one jump with the jump rope. After finding that number, discover the total energy expenditure, in joules, of Dominic's jump rope adventure.

mgh + .2 + .08

where m is mass, h is height jumped, and g is acceleration of gravity 9.81m/s^2

? It's late oh well.

Originally posted by AbnormalButSane
mgh + .2 + .08

where m is mass, h is height jumped, and g is acceleration of gravity 9.81m/s^2

? It's late oh well.

M = 100 kg

H = .25 meters.

Yeah, I'm much too lazy to use math with numbers.

Originally posted by AbnormalButSane
Yeah, I'm much too lazy to use math with numbers.


Word problems are pretty much what every single physics problem I had, were.



My least favorite was fluid dynamics. The pressure...flow rates.

AAAAHH! I hated it.