Stormwatch Vs JLA

Text-only Version: Click HERE to see this thread with all of the graphics, features, and links.



Prep-Man
This battle will happen soon. I hope.

Jack Hawksmore
Martian Manhunter
Apollo
Midnighter
Jenny Quantum
The Engineer
Adam One
The Projectionist
The Eminence of Blades
I know we don't know the new characters, so just use the existing ones.


http://media.comicvine.com/uploads/1/10837/1852632-stormwatch_large.jpg

vs

http://media.comicvine.com/uploads/6/66037/1878233-screen_capture_large.png

Q99
I just noticed, is Apollo now bald? Sucks if true.

Anyway! The JLA should win, if they can stop Jenny from winning things single-handed they'll come on top through simple power. Deadman or Flash should be able to remove Jenny from the equation. So, there you go.

Prep-Man
Na, he has hair, it just the angle.

Prep-Man
BTW, you got the god of cities, god of the internet, god of blades, god of time, god of tactics, etc... Should be a good match.

Bentley
Pretty much Jenny vs Speed.

753
Originally posted by Bentley
Pretty much Jenny vs Speed. she'd win. is the doctor gonna come back? hoping for habib specifically

Q99
Originally posted by Prep-Man
BTW, you got the god of cities, god of the internet, god of blades, god of time, god of tactics, etc... Should be a good match.

But we don't really know, Adam One, The Projectionist, or The Eminence of Blades yet.

Digi
Originally posted by 753
she'd win. is the doctor gonna come back? hoping for habib specifically

As of the end of WS, Habib was no longer the current Doctor. So it's doubtful.

Q99
Originally posted by Bentley
Pretty much Jenny vs Speed.

Don't forget Deadman, possession would work too.

Bentley
Originally posted by Digi
As of the end of WS, Habib was no longer the current Doctor. So it's doubtful.


Jenny isn't the current spirit of the twenty one century either. Who is the Doctor btw? I didn't read SW after the end of the last Authority series.

Text-only Version: Click HERE to see this thread with all of the graphics, features, and links.