GT Goku vs. Buus

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DeadpoolXXX
This is Goku from GT. He starts in his base state and can go as high as SS1 if he needs to. How far does he get?

1. Fat Buu
2. Super Buu
3. Buutenks
4. Buuhan
5. Kid Buu

If he gets past those he moves to the bonus round.
BONUS ROUND-
SSJ Vegetto


-Goku is fully healed after each round.

StiltmanFTW
He cleans.

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- Rildo was already stronger than Majin Buu and Base Goku went toe to toe with him

- Goku's GT SSJ1 multiplier is specifically said to be 100x

BrolyBlack
This is a clear stomp, he clears in his base form

Galan007
Goku stated that he could have beaten Fat Boo as SSJ3 if he would've taken the fight seriously, and also stated that he could have beaten Pure Boo if he would've had enough stamina left to powerup as SSJ3. IOW, base GT Goku(who was ~/> SSJ3 Z Goku) would beat Fat & Pure Boo.

For Super Boo and above Goku would likely have to use SSJ. The difference between SSJ3 Goku and Super Boo depends almost entirely on where you rank Gotenks during the Boo arc, though. Some people believe that post-RoSaT base Gotenks ~ SSJ3 Goku, based on Goku's Metamoran-wank before the kids had even fused -- which would put SSJ3 Gotenks somewhere around 400x SSJ3 Goku. Personally, I do not think the difference between SSJ3 Goku and Super Boo/Gotenks is even remotely close to that...mainly because I don't know how Boo could have possibly become hundredS of times more powerful, just by eating a piece of himself...but I've seen people argue the point ad nauseum. Super Boo IS a good deal more powerful than SSJ3 Goku, though -- we do know that much for sure. /shrug

Anywho, SSJ3 Gotenks ~ Super Boo, which means Bootenks is a about 2x Super Boo. And because Mystic Gohan was stomping Super Boo pretty easily, but was then stomped decisively by Bootenks, we know that Gohan was around 1.5x Super Boo. So Boohan would be roughly 2.5x Super Boo.

Vegito is a complete wildcard. All we can say for sure is that he was FAR more powerful than Boohan, but weaker than Beerus was when he stomped SSJ3 Goku at the beginning of BoG.

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