I amend my idea. I think the bifurcation buckling with compression is what caused the shattering of the "marble" stuff. So the number will be much smaller. I don't have an estimate to give because there are too many unknowns.
BT: dude...don't bypass the ban just to respond or something. Just let it sit out and pick up this discussion when you come back.
Using compression Smithel Jr. Sr. crushes a 1 ton rock.
For the sake of the example the rocks compression strength is 100MPa and its Surface Area is 2.5m^2
Compression strength[Pa] = Area[m^2] / Load[N]
100,000,000 Pa * 2.5m^2 = 250,000,000 Newtons.
So Smithel Jr. Sr. used 2.5e8N to crush that 1 ton rock.
Is this correct? Ive seen others do similar calcs so I'm sure the formula is right, however that final figure seems too high. The force needed to crush a 1 ton rock being the same force needed to move 800 tons at Mach 1? :/
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There's cleavage's in rocks, structural irregularities which could vastly differ in compression strength requirements, and the fact that the forces were applied with his hands (over a much much smaller surface area, making it easy to crush the rock than your calculation).
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Last edited by dadudemon on Sep 13th, 2012 at 08:01 AM
Lets call it a factory made rock, so no cleavages or irregularities in this rock. Just an all-in-all 100MPa rock.
1. If the whole rock was crushed in one instantaneous movement, so no ever increasing cracks being formed from the area his hands are on, wouldn't the rocks SA be used? One of the examples where I got the idea from.
2. What if the whole rock was covered by his hands? He has Mr Fantastics hands in this example.
__________________
"Gonna need more chloroform..."
"If you look down on us, judge us, condemn us... then you shall fear us!"