4011
😂
Well, the hex-game works with 16... ie to get the number in binary, you multiply the last digit with 16^0=1, the second one with 16^1=16, the third one with 16^2=?256 etc
Here it's with 5... always multiply 5 with itself, once less than the number of the digit counted from the right 😑 uummm now that i write it i dont really understand it anymore 😂
well, the last digit is 5^(#-1)=5^0=1
second from the right is 5^(#-1)=5^1=5
third from the right is 5^2=25
fourth is 5^3=125
... and as the last digit is in this post counted once (4011) it's 1x1=1
second one is also 1... 1x5=5
0x25=0
4x125=500
... =506 😉