Invisible Woman vs Wolverine

Started by xmarksthespot3 pages

Invisible Woman vs Wolverine

The fight occurs in an adamantium room.

The room is a 6x6x6 foot cube.

It's illuminated inside and air can get in and out because a wizard did it.

They start in opposite corners of the room.

Discuss.

Yes, I can see the other thread too. But I was making this one first. 🙁

Sue. Easily.

Claw blitz

I think Wolverine could cover the six feet before she raised a shield and from there he only needs to hit her once, claws or not.

Canadian blitz for the win!

Or, ya know, Sue wins.

Originally posted by srankmissingnin
I think Wolverine could cover the six feet before she raised a shield and from there he only needs to hit her once, claws or not.
Pythagoras' Theorem.

Originally posted by srankmissingnin
I think Wolverine could cover the six feet before she raised a shield and from there he only needs to hit her once, claws or not.

Who drew Grifter in your avatar?

This all hinges on whether or not Wolverine can get to her fast enough. That's not enough to give him a majority win IMO.

IW ftw frost3et

Originally posted by srankmissingnin
I think Wolverine could cover the six feet before she raised a shield and from there he only needs to hit her once, claws or not.

I beg to differ.

http://img174.imageshack.us/my.php?image=scan0012ii0.jpg

That is, unless Wolverine is faster than lightning now.

Originally posted by Lucid Lui
This all hinges on whether or not Wolverine can get to her fast enough. That's not enough to give him a majority win IMO.

It's only six feet... and he only needs to move three to be able to deck her. Shouldn't be a problem to get the majority IMO.

Originally posted by Metalmanx
I beg to differ.

http://img174.imageshack.us/my.php?image=scan0012ii0.jpg

That is, unless Wolverine is faster than lightning now.

Clor gave a warning though.

Originally posted by srankmissingnin
It's only six feet...
Diagonal corners. Pythagoras' Theorem.

Originally posted by srankmissingnin
It's only six feet... and he only needs to move three to be able to deck her. Shouldn't be a problem to get the majority IMO.

8 and a bit feet..a bit less then 8.5 ish....there in opposite corners remember....but then again what's a few feet...

There's a reason I chose a 6x6x6 dimensions... aside from the fact that Sue is 5'6 and Wolverine is 5'3.

Originally posted by ExodusCloak
8 and a bit feet..a bit lesst then 8.5 ish....there in opposite corners remember....but then again what's a few feet...

Oh, I missed reading that they were in opposite corners, just assumed they were just leaning against a wall. My mistake

Originally posted by Metalmanx
I beg to differ.

http://img174.imageshack.us/my.php?image=scan0012ii0.jpg

That is, unless Wolverine is faster than lightning now.

You need to read between the panels Metalmanx. I interpreted that as Sue throwing up that shield the moment clone Thor said "You're all going down," before he actually summoned the lighting (since it was pretty clear what his intentions where). Unless... unless you think Sue is faster then light.

Originally posted by xmarksthespot
Diagonal corners. Pythagoras' Theorem.

I was wondering why you were going on about the Pythagorean Theorem just seemed stranged before it was pointed out they where in opposite corners of the room lol

Originally posted by srankmissingnin
I was wondering why you were going on about the Pythagorean Theorem just seemed stranged before it was pointed out they where in opposite corners of the room lol
Accounting for the volume occupied by their bodies they're pretty much 2 metres apart.

Doesn't Sue conjure her shields with a thought?

And Wolverine can't move at the speed of thought, last time I checked.

Sue wins.