Originally posted by KharmaDog
O.k. That was funny.A tutor helps you figure the answers out yourself.
He may. I just question the process.
He said, any help is appreciated. I'm pretty certain he would ask how they did it.
If I could answer that (formerly a mechanical engineering major), I would offer an explanation of how to get there but it's been three years since I've done any serious math.
Originally posted by inimalist
omghe doesn't know something!
critisize him for asking his peers!1!!1
real intellectual people actually never ask eachother things they don't know. its like a sign of weakness. If you aren't careful, some young and ambitious intellectual can steal your mind power if they knew of such weaknesses!
You score! Thanks for completely missing my point!
Originally posted by inimalistNah, to be wrong should be great, as it brings you to a new level of awareness.
omghe doesn't know something!
critisize him for asking his peers!1!!1
real intellectual people actually never ask eachother things they don't know. its like a sign of weakness. If you aren't careful, some young and ambitious intellectual can steal your mind power if they knew of such weaknesses!
Originally posted by KharmaDog
I have a suggestion, earn your "bonus" marks yourself. In the real world, it's the people who help themselves that succeed, that's one of the lessons they used to teach in University.
In the real world you can and should go ask for help. Those that never learn that get weeded out pretty well too (unless you expect everyone to be Newton or Cavendish).
Originally posted by KharmaDog
Uhm... is anyone else thinking that it is rather lame to ask for help with your homework on a open forum?I have a suggestion, earn your "bonus" marks yourself. In the real world, it's the people who help themselves that succeed, that's one of the lessons they used to teach in University.
As for the lazy asses, cheaters and those looking for the easy out, they're usually sorted out in time.
They teach a lot of lies like that in University, it's a shame really.
I have never done trigonomic derivatives. I have never done quotient derivatives. I got lost on the first one when I attempted it. I didn't even bother with the second since I have never done those kind. I assume you're trying to find the first derivative.
🙁
It's been 6 years and 7 months since I have studied derivatives. We didn't mix and match the equations up into complex mixed quotients, though.
Send a PM to Abnormalbutsane. She is/was taking calculus and derivatives are not difficult IF you know how to do them. She's a smart person and this should be easier for her.
Re: Anyone An Expert in Calculus?
Originally posted by Dr. Leg Kick
Having trouble with these few bonus problems. I dont' need to simplify, just find the derivative. any help is really appreciated.
First Link:
1st problem- Looks like a trig identity. You should have a list of trig identities in the back of your book. I might be mixing up calc I and calc II though. It's been a while, and I don't have my book on me.
2nd problem- combine 2x and sqrt(x) (or 2x^3/2) and then do product rule.
Second Link:
1st problem- Can be re-written as (5e^x)*(sec(x)). Product rule that. In the second portion, distribute ln(x) to 3x and x^4*sinx. Prepare for more product rule bukakke.
2nd problem- treat secx^2 as f(x) and (e^2x + 1)^1/2 as g(x). Moar product rulez! Solution should be the derivative over the original equation since it's a ln derivative.
Again I must emphasize that it's been a while since I took Calc, so I might be off on something. Then again, if I don't remember it, my TI-89 usually does lol.
Originally posted by AngryManateethanks for attempting man, appreciate it, but i got the q's done and got them right.
First Link:1st problem- Looks like a trig identity. You should have a list of trig identities in the back of your book. I might be mixing up calc I and calc II though. It's been a while, and I don't have my book on me.
2nd problem- combine 2x and sqrt(x) (or 2x^3/2) and then do product rule.
Second Link:
1st problem- Can be re-written as (5e^x)*(sec(x)). Product rule that. In the second portion, distribute ln(x) to 3x and x^4*sinx. Prepare for more product rule bukakke.
2nd problem- treat secx^2 as f(x) and (e^2x + 1)^1/2 as g(x). Moar product rulez! Solution should be the derivative over the original equation since it's a ln derivative.
Again I must emphasize that it's been a while since I took Calc, so I might be off on something. Then again, if I don't remember it, my TI-89 usually does lol.
by the way, nice beamer. i had a X5 3.0 06'. that car was aggressive, the drive was uncomfortable though. now driving a Cayenne.
my friend just got the new 335. he loves it. the drive is aggressive, and again somewhat uncomfortable, but regardless, beamers are amazing.
