Originally posted by Scythe
Really? I didn't view it as Sam going to robot heaven. I find it very unique and interesting how different people saw things on-screen. I love that. Like, I saw Sam's visit with the Primes and saw it as an out of body experience, something similar to a dream sequence, like that. My cousin thought it was the Matrix' reaction to jumpstart his body back to the living with a message.
yeah, robot heaven was the last thing on my mind
Originally posted by Scythe
Really? I didn't view it as Sam going to robot heaven. I find it very unique and interesting how different people saw things on-screen. I love that. Like, I saw Sam's visit with the Primes and saw it as an out of body experience, something similar to a dream sequence, like that. My cousin thought it was the Matrix' reaction to jumpstart his body back to the living with a message.
Originally posted by Doctor-Alvis
Ha, yeah. I thought it was Sam going to the "Prime dimension", like in the Authority comics. The Doctor could go to this trippy dreamland place where all the previous shamans before him are and he can ask them for advice and stuff. Like that, but with Primes.
Neat. Similar to what I thought as well.
Originally posted by Sadako of Girth
It was done in the cartoon "The rebirth" also.
There were a few vector sigma mergances in the series also.....
Right before it got all crazy!! Haha.
Originally posted by CadoAngelus
The bit where Sam meets Megatron...again:- How does the car door miraculously open?
- Wouldn't a 80ft drop through an abandoned warehouse roof kill them? Because something tells me a car would've sustained a hell of a lot more damage than a broken bumper...wtf?!
Well, first, let's use my numbers, and then we'll use yours.
Let's pretend it was a straight drop for 3 seconds.
9.8m/s/s for three seconds equals an end velocity of 29.4 meters a second, by the time it impacts.
We need to put that into something that you would understand..so...convert that to meters an hour...
60 seconds in a minute. 60 minutes in an hour.
29.4*60*60
105840 meters an hour.
Convert to KM an hour.
105840/1000
105.84 KMH.
Because stupid Yanks and Brits are still too arrogant to use the metric system, I'll be nice and convert that to mils and hour.
105.84*.62137
65.8 mph.
That would be quite a wreck considering the "other side" isn't giving very like two cars in a head on collision would. It's like a crash test in the lab, except NOT at 35 MPH like they usually do. It's almost 66 MPH.
However, they crashed through a building and were dropped from a much smaller distance. 80 feet actually sounds about right, judiging the distance on the film.
So lets figure out the end velocity when dropped from 80 feet.
The forumula, as far as I can remember (I couldn't find it in a couple of seconds...so I gave up. Lazy, I know....) is
Vf^2 = (Vi^2)+2*a*d
Vi is initial velocity which = 0
a is acceleration which = 32f/s/s (since you gave yours in feet...I'll use English units. 🙁 )
d is distance or displacement in the vector = 80 feet
So we are only left with sqrt(2*a*d) which is sqrt(2*32*80) which is 71.55 feet a second.
Let's transfer this to feet an hour.
71.55*3600 (again, 60*60)
257595.03 feet an hour
Let's convert to miles an hour
257595.03/5280
That comes to 48.79 MPH.
Definitely surviveable especially if you consider it wasn't a straight, clean, drop. Their actual final velocity was probably less than 48 MPH.
They had airbags in the front and the guy seemed buckled up. I don't remember if they buckled up or not.
Edit- Now, I'm going to be honest here. The stunt effects team/supervisor are very much aware of this info already and there are probably even little books that they carry that have all of this stuff calculated for them, already. (I see the mythbusters carrying around a similar book that has a lot of this stuff in it for them....and they were effects guys...so no reason that a move this big wouldn't have people knowledgable about this stuff.) I would assume that after so many movies and doing effects school, they hve these things memorized or have a general feel for what is acceptable for an effect without being stupid. They probably go, "K, let's show the shot while holding the car, at about 50 feet and drop it from there. Next shot, we'll drop the car from 10 feet on the "slowed pulley" system with the dummies/stunt men. Let's do this." Then the break and work on that shot for the week. Effects can make the distance further...and it does appear to be between 50-100 feet.
Originally posted by dadudemon
Well, first, let's use my numbers, and then we'll use yours.Let's pretend it was a straight drop for 3 seconds.
9.8m/s/s for three seconds equals an end velocity of 29.4 meters a second, by the time it impacts.
We need to put that into something that you would understand..so...convert that to meters an hour...
60 seconds in a minute. 60 minutes in an hour.
29.4*60*60
105840 meters an hour.
Convert to KM an hour.
105840/1000
105.84 KMH.
Because stupid Yanks and Brits are still too arrogant to use the metric system, I'll be nice and convert that to mils and hour.
105.84*.62137
65.8 mph.
That would be quite a wreck considering the "other side" isn't giving very like two cars in a head on collision would. It's like a crash test in the lab, except NOT at 35 MPH like they usually do. It's almost 66 MPH.
However, they crashed through a building and were dropped from a much smaller distance. 80 feet actually sounds about right, judiging the distance on the film.
So lets figure out the end velocity when dropped from 80 feet.
The forumula, as far as I can remember (I couldn't find it in a couple of seconds...so I gave up. Lazy, I know....) is
Vf^2 = (Vi^2)+2*a*d
Vi is initial velocity which = 0
a is acceleration which = 32f/s/s (since you gave yours in feet...I'll use English units. 🙁 )
d is distance or displacement in the vector = 80 feet
So we are only left with sqrt(2*a*d) which is sqrt(2*32*80) which is 71.55 feet a second.
Let's transfer this to feet an hour.
71.55*3600 (again, 60*60)
257595.03 feet an hour
Let's convert to miles an hour
257595.03/5280
That comes to 48.79 MPH.
Definitely surviveable especially if you consider it wasn't a straight, clean, drop. Their actual final velocity was probably less than 48 MPH.
They had airbags in the front and the guy seemed buckled up. I don't remember if they buckled up or not.
Edit- Now, I'm going to be honest here. The stunt effects team/supervisor are very much aware of this info already and there are probably even little books that they carry that have all of this stuff calculated for them, already. (I see the mythbusters carrying around a similar book that has a lot of this stuff in it for them....and they were effects guys...so no reason that a move this big wouldn't have people knowledgable about this stuff.) I would assume that after so many movies and doing effects school, they hve these things memorized or have a general feel for what is acceptable for an effect without being stupid. They probably go, "K, let's show the shot while holding the car, at about 50 feet and drop it from there. Next shot, we'll drop the car from 10 feet on the "slowed pulley" system with the dummies/stunt men. Let's do this." Then the break and work on that shot for the week. Effects can make the distance further...and it does appear to be between 50-100 feet.
seems plausible, and it would be survivable - considering your analogy to a car crash - but the car was practically untouched (like i said, a broken bumper).
you've shed light on the situation and i've considered that they would've survived given the circumstances, but i'm still adamant that the car would've sustained a hell of a lot more damage - to use the car crash analogy again - a car crash at 48MPH would probably end in most of the front of the car being destroyed and crumpled, maybe at a push some of the other crumple zones being triggered, and worst case passenger or driver's being broken...
otherwise i've got no problem with your conclusion
Originally posted by CadoAngelus
seems plausible, and it would be survivable - considering your analogy to a car crash - but the car was practically untouched (like i said, a broken bumper).you've shed light on the situation and i've considered that they would've survived given the circumstances, but i'm still adamant that the car would've sustained a hell of a lot more damage - to use the car crash analogy again - a car crash at 48MPH would probably end in most of the front of the car being destroyed and crumpled, maybe at a push some of the other crumple zones being triggered, and worst case passenger or driver's being broken...
otherwise i've got no problem with your conclusion
Oh, no, I fully agree. As I hinted in my edit, they did the scene in "two" edited shots. (Probably closer to 4.)
The second shot was a drop from a slowed pulley system from about ten feet, and the edit removes the pulley from the back end, and the "start" of the drop.
You are absolutely correct that the car would have sustained much more damage. We would have seen the frame bend, the front end crumple, big time, and the windshield and windows bust completely.
It looks like they gave them "battle" damage that would be similar to a 48 mph wreck, namely, cuts on the head and face.
However, the car didn't drop straight down as it crashed through the warehouse. It wouldn't have been a complete 48 mph.
But, yes, you're right. They would have survived with little injury. The glass would have been the biggest injury cause.
Originally posted by Sadako of Girth
Absolutely. A nice presentation, DDM, but that scene in the movie was cleeeeeearly bollocks.
Thank you very much, Sadako. Sometimes, I feel like no one cares about all of the math stuff I do. 🙁
Originally posted by dadudemon
Oh, no, I fully agree. As I hinted in my edit, they did the scene in "two" edited shots. (Probably closer to 4.)The second shot was a drop from a slowed pulley system from about ten feet, and the edit removes the pulley from the back end, and the "start" of the drop.
You are absolutely correct that the car would have sustained much more damage. We would have seen the frame bend, the front end crumple, big time, and the windshield and windows bust completely.
It looks like they gave them "battle" damage that would be similar to a 48 mph wreck, namely, cuts on the head and face.
However, the car didn't drop straight down as it crashed through the warehouse. It wouldn't have been a complete 48 mph.
But, yes, you're right. They would have survived with little injury. The glass would have been the biggest injury cause.
Thank you very much, Sadako. Sometimes, I feel like no one cares about all of the math stuff I do. 🙁
Wow, Oh happy day we actually agree on something 💃 Good calculations.
I can't remember did the car land on it's wheels? and did Sam have time to get his seat belt on?
If it landed on it's wheels, the people in the car would of probably had some spinal injuries.
It hit nose first then fell over...!!!
Thats what makes it so bloody unrealistic. That car's engine would be in the rear trunk afterhaving crushed at least Sam and Mikkaela Mikala, Michaela, Michaelaby whatever her name is, maiming Leo horribly (Hurrrrrrrah!) or ejecting him through the windscreen and into the floor on impact.
Pure PR bollocks on behalf of the car company that Bay probably got money for advertising into the licencing. And werent the airbags meant to deployed when the car was rammed through the pretender and in to the lamppost...? Pure silliness.
Originally posted by Sadako of Girth
It hit nose first then fell over...!!!Thats what makes it so bloody unrealistic. That car's engine would be in the rear trunk afterhaving crushed at least Sam and Mikkaela Mikala, Michaela, Michaelaby whatever her name is, maiming Leo horribly (Hurrrrrrrah!) or ejecting him through the windscreen and into the floor on impact.
No. The car wouldn't have been traveling fast enough for any of that to happen.
Also, I think they buckled up. After they got Sam back in, I could have sworn that at least Sam had a buckled up fest. I mentioned this earlier.
Besides, it's hollywood. Even the cult classic, Resivoir Dogs, has so many ****-ups similar to or worse than the front end not crumpling.
Originally posted by Sadako of Girth
Pure PR bollocks on behalf of the car company that Bay probably got money for advertising into the licencing. And werent the airbags meant to deployed when the car was rammed through the pretender and in to the lamppost...? Pure silliness.
That last point is correct. I was wondering the same thing in the theater, when I saw it. I think one of us needs to sign into IMDB and write that into the goofs section.
Originally posted by dadudemon
Well, first, let's use my numbers, and then we'll use yours.Let's pretend it was a straight drop for 3 seconds.
9.8m/s/s for three seconds equals an end velocity of 29.4 meters a second, by the time it impacts.
We need to put that into something that you would understand..so...convert that to meters an hour...
60 seconds in a minute. 60 minutes in an hour.
29.4*60*60
105840 meters an hour.
Convert to KM an hour.
105840/1000
105.84 KMH.
Because stupid Yanks and Brits are still too arrogant to use the metric system, I'll be nice and convert that to mils and hour.
105.84*.62137
65.8 mph.
That would be quite a wreck considering the "other side" isn't giving very like two cars in a head on collision would. It's like a crash test in the lab, except NOT at 35 MPH like they usually do. It's almost 66 MPH.
However, they crashed through a building and were dropped from a much smaller distance. 80 feet actually sounds about right, judiging the distance on the film.
So lets figure out the end velocity when dropped from 80 feet.
The forumula, as far as I can remember (I couldn't find it in a couple of seconds...so I gave up. Lazy, I know....) is
Vf^2 = (Vi^2)+2*a*d
Vi is initial velocity which = 0
a is acceleration which = 32f/s/s (since you gave yours in feet...I'll use English units. 🙁 )
d is distance or displacement in the vector = 80 feet
So we are only left with sqrt(2*a*d) which is sqrt(2*32*80) which is 71.55 feet a second.
Let's transfer this to feet an hour.
71.55*3600 (again, 60*60)
257595.03 feet an hour
Let's convert to miles an hour
257595.03/5280
That comes to 48.79 MPH.
Definitely surviveable especially if you consider it wasn't a straight, clean, drop. Their actual final velocity was probably less than 48 MPH.
They had airbags in the front and the guy seemed buckled up. I don't remember if they buckled up or not.
Edit- Now, I'm going to be honest here. The stunt effects team/supervisor are very much aware of this info already and there are probably even little books that they carry that have all of this stuff calculated for them, already. (I see the mythbusters carrying around a similar book that has a lot of this stuff in it for them....and they were effects guys...so no reason that a move this big wouldn't have people knowledgable about this stuff.) I would assume that after so many movies and doing effects school, they hve these things memorized or have a general feel for what is acceptable for an effect without being stupid. They probably go, "K, let's show the shot while holding the car, at about 50 feet and drop it from there. Next shot, we'll drop the car from 10 feet on the "slowed pulley" system with the dummies/stunt men. Let's do this." Then the break and work on that shot for the week. Effects can make the distance further...and it does appear to be between 50-100 feet.
you are my new heronotworthy