Originally posted by Kovacs86
Hate to do this to you, Steve, but actually it should be..."Steve, you're a comedy genius and would make a good English teacher."
...you're now on my list of people to kill...haven't actually made a list but when I do you had better watch out Mr. Kovacs86 if that is indeed your real name ahah
Originally posted by Kazenji
Whats the link with Gambit and Wolverine ?
They're both hugely overrated, over-powered characters.
Originally posted by Kazenji
[B]And also as i said in another thread, iI would like to know how they've tied cyclops into this because with X-men 1 when he see's wolverine its as if he's never met him.
Cheap, stupid attempt to tie into the X-Men series and attract more people to see their shit. It's all a bit of a mess, by the sound of it.
Originally posted by Kazenji
Whats the link with Gambit and Wolverine ?they also did it with Weapon X first class comic
And also as i said in another thread, iI would like to know how they've tied cyclops into this because with X-men 1 when he see's wolverine its as if he's never met him.
Thats because in the x-men movie he hadn't met him til then...think about it when wolverine breaks the mutants out cyclops can't see so he had never met him and he didn't know it was wolvie who helped him
Originally posted by Kazenji
Whats the link with Gambit and Wolverine ?they also did it with Weapon X first class comic
And also as i said in another thread, iI would like to know how they've tied cyclops into this because with X-men 1 when he see's wolverine its as if he's never met him.
yea in the comic gambit broke in during the time wolverine was escaping.
He never meets wolverine in the movie, never physically see him
Re: Re: Deadpool (Wolverine movie images)
Originally posted by WO Polaski
he looks like a gay version of Voldemort.
A gay version of Voldemort? As apposed to what exactly? The manly straight version of Voldemort?
😕
The dude is about as androgynous and sexually ambiguous as they get... plus he is a wizard which is already pretty gay in its own right.