Assuming Spidey can exert 20tons maximum, spidey accelerates the being 1 meter before throw, and neglecting air resistance then Spidey throws
1. About 1600 feet (weighs about 160lb) Homerun
2. About 1450 feet (weighs about 180lb) Homerun
3. About 600 feet (weighs about 400lb right?) Homerun
4. About 164 feet (weighs about 1600lb) Shallow Outfield
8. About 276 feet (weighs about 950lb) Mid Outfield
If Spidey can exert 40 tons (he has several of these feats) then double these numbers. If Spidey can exert 100 tons (he has several class 100 feats) then multiply these numbers by 5.
In reality air resistance should knock a fraction off these numbers. The more stronger spidey is then the larger the fraction gets knocked off.
Originally posted by Tha C-Master
You mean the larger percentage or amount? Because the percentage could be the same but it would take more off at higher velocities of course.
Drag force is proportional to the square of the velocity. So if you throw something twice as fast then you gain 4 times the drag (retarding force).
So the object will go farther is thrown faster. You just get the law of diminishing returns.
Originally posted by h1a8the strength scale is based off of the military press, so the characters total body strength is not known. you don't even use your legs to military press.
Assuming Spidey can exert 20tons maximum, spidey accelerates the being 1 meter before throw, and neglecting air resistance then Spidey throws1. About 1600 feet (weighs about 160lb) Homerun
2. About 1450 feet (weighs about 180lb) Homerun
3. About 600 feet (weighs about 400lb right?) Homerun
4. About 164 feet (weighs about 1600lb) Shallow Outfield8. About 276 feet (weighs about 950lb) Mid Outfield
If Spidey can exert 40 tons (he has several of these feats) then double these numbers. If Spidey can exert 100 tons (he has several class 100 feats) then multiply these numbers by 5.
In reality air resistance should knock a fraction off these numbers. The more stronger spidey is then the larger the fraction gets knocked off.
spider-man basically did a hammer throw to toss that alligator so the calculation for that is way different (plus 45 degree trajectory has to be accounted for).
simplest way you could do it is to exchange the weights of the characters with the alligator's, but then the alligator's landing point and weight is unknown so..... dead end