Alright, this is gonna be some franken math, so bare with me. 9.8 m per s^2 = accelleration due to gravity.
What we need to do to determine the distance of Samus toss is something like the following.
If we assume she launches the javelin at 45 degrees, then half of her speed will be used for vertical travel, and half for horizontal.
So, we'd need to figure out how long the accelleration of gravity takes to bring the javelin's height back down to 0, then determine the average horizontal speed due to wind resistance.
It should easily be a couple miles.
So, let's get cracking. Let's assume the speed booster makes her move at mach 2.
If that's so, her total innitial throw velocity is 680 m/s
Therefore, her vertical innitial velocity is 340 m/s
For the accelleration to gravity to catch up will take more than a couple seconds to totally reverse this. I wish I had a graphing calculator.
I'll just represent it step by step.
I'll return with more on this.