who organized time ?

Originally posted by King Kandy
Maybe so, but I still want to know what the original point was.

You mean why some cultures chose 7 some 10, etc.?

Well 7 apparent is about 1/4th of the moon phase, so that's probably why one might choose 7.

Originally posted by Bardock42
You mean why some cultures chose 7 some 10, etc.?

Well 7 apparent is about 1/4th of the moon phase, so that's probably why one might choose 7.

Originally posted by chomperx9
who organized and decided on how the time works in life ?

for example there is 24 hrs a day 60 mins an HR 60 secs a min how come they decided on that and not 48 hrs a day and 30 mins an hr

and who ever decided on it how did he or she convice the entire world to follow that ?

like maybe in some countries im sure they would have disagreed with how the time got organized since other contries fight over religion and stuff since day 1 why dont they argue over time and dates. like maybe on their calendar they wanted it to be 365 days a year but more months with less days.

how did it get all straighten out and who organized it to how it is today ?

father time did 😛

Originally posted by Symmetric Chaos
A Lorentz factor of 86400 is reached at 0.9999999999330204c. There are 86400 seconds in one day. QED

HOOORAY! I found it. All I needed was a lead, and Lorentz factor did it fer me, instuff. Thanks, man.

Wait, I did the math, and I'm not getting the same thing as you. I got .999988....bla bla bla.

I'll have to read over about it, again, but show me what you did, if you read this before I get back.

Originally posted by dadudemon
Wait, I did the math, and I'm not getting the same thing as you. I got .999988....bla bla bla.

I'll have to read over about it, again, but show me what you did, if you read this before I get back.

I didn't do any math except to figure out how many seconds there are in a day.

http://www.1728.com/reltivty.htm (4th button)

But lets go through the math as I understand it:

t = t'/(1-v^2/c^2)^1/2

t=outside time
t'=own time
v=a fraction of light speed

using wolfram|alpha:

86400 = 1/(1-(vc)^2/c^2)^1/2
which reduces to
86400=1/(1-v^2)^1/2
which reduces to
(7464959999^1/2)/86400
which equals
0.99999999993302.....

Originally posted by Bardock42
Man, you ask the most insane question, bro.

Maybe there is a planet that spins incredibly quick? Reminds me of that one Star Trek episode..I can't remember what is was, but some ship was witnessing the birth and evolution of a species on a planet in real-time. Seconds were passing in space, but on the surface of the planet time was moving at a much faster rate.

This thread is blowin' my mind.

Originally posted by Symmetric Chaos
I didn't do any math except to figure out how many seconds there are in a day.

http://www.1728.com/reltivty.htm (4th button)

But lets go through the math as I understand it:

t = t'/(1-v^2/c^2)^1/2

t=outside time
t'=own time
v=a fraction of light speed

using wolfram|alpha:

86400 = 1/(1-(vc)^2/c^2)^1/2
which reduces to
86400=1/(1-v^2)^1/2
which reduces to
(7464959999^1/2)/86400
which equals
0.99999999993302.....

Yeah, your math works out correctly.

However, I dont' know where you got your C from in second step:

86400 = 1/(1-(vc)^2/c^2)^1/2

How did you go from:

86400= 1/(1-(v^2)/(c^2))^1/2

to

86400 = 1/(1-(vc)^2/(c^2))^1/2

An extra C was added to the the bottom numerator.

I used the identity and came up with 86400 = 1/(((C^2)-(v^2))/(c^2))^(1/2)

That still does not equal your work.

I assume C = 29979000 m/s

I also assume v is not 0 and is positive (lulz).

(86400^2 - 1) = 7464959999

So, I understand where that number came from (I assume that, eventually, the 1 is subtracted from the other side at some point after the square root is elminated from each side.)

I think this is just a problem of me forgetting how to do algebra.

I didn't know if it was useful, so I found the derivative:

-((2 v^2)/(C^3)-(2 v v'(C))/C^2)/(2 (1-(v^2)/C^2)^(3/2)) (This took a while.)

I didn't find a use for this...but I thought it would help.

I found what the derivative would be if it was divided by -((2 v^2)/(C^3)-(2 v v'(C))/C^2)/(2 (1-(v^2)/C^2)^(3/2))

Any guesses?

Originally posted by Bardock42
I found what the derivative would be if it was divided by -((2 v^2)/(C^3)-(2 v v'(C))/C^2)/(2 (1-(v^2)/C^2)^(3/2))

Any guesses?

No. 😐

Originally posted by dadudemon
Yeah, your math works out correctly.

However, I dont' know where you got your C from in second step:

86400 = 1/(1-(vc)^2/c^2)^1/2

How did you go from:

86400= 1/(1-(v^2)/(c^2))^1/2

to

86400 = 1/(1-(vc)^2/(c^2))^1/2

Since I was solving for velocity I couldn't write out the value of v. However all possible speeds can be written as a value (between 1 and 0) multiplied by c. I probably should have written it as:

86400= 1/(1-(v^2)/(c^2))^1/2

where v = x*c

and then

86400= 1/(1-((xc)^2)/(c^2))^1/2

Originally posted by Symmetric Chaos
Since I was solving for velocity I couldn't write out the value of v. However all possible speeds can be written as a value (between 1 and 0) multiplied by c. I probably should have written it as:

86400= 1/(1-(v^2)/(c^2))^1/2

where v = x*c

and then

86400= 1/(1-((xc)^2)/(c^2))^1/2

Dude, that's sweet. Makes perfect sense and it puts into perspective what each of the variables represent.

It was a slow morning at work, today, so I had time to pretend to know what I was doing.

Originally posted by dadudemon
It was a slow morning at work, today, so I had time to pretend to know what I was doing.

that has little to do with a slow morning at work, or it being today

Originally posted by dadudemon
No. 😐

It's 1.

1!

Originally posted by inimalist
that has little to do with a slow morning at work, or it being today

Context.

Slow morning at work means: I had time to mess around with this and waste time.

Originally posted by Bardock42
It's 1.

1!

I thought you meant to find the derivative of the derivative and divde that by derivative.

Originally posted by dadudemon
Context.

Slow morning at work means: I had time to mess around with this and waste time.

fair enough, the joke was that you generally pretend at what you are doing 😉

Originally posted by dadudemon

I thought you meant to find the derivative of the derivative and divde that by derivative.

That's way too bothersome. Totally not me.

Richard Stengel,
Managing Editor

Originally posted by Bardock42
That's way too bothersome. Totally not me.

Indeed. That's why I gave you the plain "no" with the straight face. No way in hell I was going to do that. 😐

Originally posted by inimalist
fair enough, the joke was that you generally pretend at what you are doing 😉

Makes sense. hmm

If someone came over to my desk, they'd think I was doing work because it looked like I was doing math. (in actuality, it was me trying to figure out how the **** SC got what he got, but not getting anywhere.)