Astner
The Ghost Who Walks
I have no idea why you decided to bump a five-month old thread. But due to the previous lack of questioning as well as your flamboyant and ignorant approach I feel that I'll have to address it.
Originally posted by 3561052011
Well to start the Coriolis force isn't a real force so it has no affect on it's velocity to a observer that isn't on the ground. I'll write more once I figure out what's he's trying to do with the cross product.
You're right in that the Coriolis force is a fictive force but what you fail to realize is that in a spherical coordinate system--which is the easiest to work in for this problem--necessitates the accounting of the Coriolis effect as you should've seen in the deduction of the formula.
To put it simple enough for you. If the earth rotates and you're traveling a global distance through a given non-earthbound trajectory you're not going to land at the same spot as if the earth didn't rotate.
Originally posted by 3561052011
This calc is ridiculous. Numerically integrate with respect to what? How can you integrate his body if you don't even have a function?
Do you even know what a numeric integration is? A numeric integration is a method to find the solution to an integral which isn't necessarily defined. In this specific problem I used MATLAB to determine the amount of pixels within the outlining drawing and then scaled it with Tao's length--as I specified--for the area in quadratic meters. Though you should be able to solve for the area with Photoshop. It's not that advanced.
Originally posted by 3561052011
You would have to approximate his body as some simple figure like a line or a cube.
Firstly, no I wouldn't have to. Secondly it's not as impressive or accurate and it's not as if it requires any great effort on an intellectual level.
Originally posted by 3561052011
If you use a 3D figure most likely this will be a triple integral using some kind of Polar or spherical coordinates.
You're confused. When I solved for Tao's and the pillar's orthogonal
area I didn't use any coordinate system, and if I would've it couldn't have been a spherical one needing solving with a triple integral. I wouldn't have used polar coordinates because they're impractical to find Tao's and the pillar's area. However, if I would've used a coordinate system I'd sticked to
general coordinates and in a step by step procedure creating one fitting the figure. Finally, I'm not deducing an expression in forms of variables relative to the system's trajectory, because it doesn't affect the body.
Area: A body spanning 2 dimensions.
Originally posted by 3561052011
The normal vector is the normal force which Tao's hands exert on the pillar.
No. A normal vector is a vector with the length one generally used to depict directions. In other words it has nothing to do with the force exerted on the pillar. It simply points in what direction Tao is throwing the pillar.
Originally posted by 3561052011
"Write down the data in your program and optimize for velocity.". That makes no sense if you have the numbers already then you would know it's velocity there is nothing to optimize.
I created a numeric function program based off the previous established formulas and units to find the velocity. Better formulated as:
"With this angle, this distance and under these conditions what's the lowest possible velocity required to solve the problem?"Originally posted by 3561052011
The Drag force equations changes at low and high speeds so it not very accurate.
No, there were two cases. Laminar flow and turbulent flow, both were accounted for but the latter didn't come into play until the last few hundred meters if I recall correctly and thus wouldn't have had to be accounted for.
Originally posted by 3561052011
This calc is garbage plain and simple.
I'd criticize your ability--or lack thereof--to comprehend elementary mathematical procedures.