Mini Me versus the Hulk

On to the Hulk lifting stuff.

With Hulk, he would retain more strength the smaller he got (relative to his body mass).

Let's assume Hulk is 15 feet tall when he chucked that tank's entire turret top like it was nothing and it flew many many miles.

Based on the stats I'm seeing of Abrams tanks on this forum:

http://208.84.116.223/forums/index.php?showtopic=27709

Looks like the turret has a mass around 21 tonnes.

Since we already know one dimension of his size, we can scale down to 3 inches. I want to convert to metric because I am becoming jaded at the crappy English Units system.

15 feet = 4.57 meters = 457 cm

3 inches = 7.62 cm

Let's pretend that he's a cube and that's the measure of one side (I KNOW it's not right, but we are doing this for simplicity's sake, just to get an idea, NOT to get an exact number. Why? We don't know his muscle fiber cross-sectional area, so we can just "fudge" a little bit and get close).

Pretend Hulk has a mass that's about 3 times as dense as a human OR about 3 g/cm^3

Let's purify Hulk into a cube shape to make our calculations easier.

How do we do that? Easy: we know his height. We can guess his density.

So what is his mass? Well, Hulk weighs 1040 lbs as the standard green Hulk at 7 feet tall.

1040 lbs = 471744 g

Divide 3g/cm^3 to get his volume.

471744g/3g/cm^3 = 157248 cm^3

We must scale that to his height of 15 feet which is 457 cm.

We can do this with the following formula

M=((b/a)^3)*m

Thanks to Astner for talking some sense into me and convincing me that that works.

Anyway, a is one dimension before transformation.

b is the same, congruent, dimension after transformation.

m is the mass before transformation.

M is the mass after transformation. Again, this is assuming two congruent 3d objects.

We must convert 7 feet to cm.

213.4 cm

(457cm/213.4cm)^3)*471744g = 4633100.7 g (or 4.6 tonnes...which is about right.)

Now we know his mass, his lifting power feat, his height before and after transformation.

So now we need to figure out how much mass he can lift AFTER transforming into a little dude. We are almost there. Using our cube as the "example" to scale, we will pretend Hulk is a cube. Since we have a fair guess on density, let's turn him into a cube and scale him down to a small cube. Essentially, we are doing the reverse of the scale up.

To find one side, first, find his volume.

We know density and we know his mass: 4633100.7g/(3g/cm^3) = 1544366.9 cm^3

That's his volume. To scale it down to a cube, fine one side by finding the cube root: (1544366.9cm^3) ^(1/3) = 115.6 cm

So that's just ONE side of our "Hulk" cube.

This is getting much easier, I assure you. We are almost there.

Our Hulk cube can perform a strength feat of 21,000,000 g. His own mass gets in the way of that feat and his mass is 4,600,000 g. Again, this is just for simpilcity's sake, even though this is not exact. So add 4,600,000g to 21,000,000g to get the total mass lifted by his muscles during that feat: 25,600,000g.

Cross-sectional area...almost. Let's keep it within our cube man. Find the ratio between the surface area of one of the sides and the total mass lifted:

(115.6cm) ^2 = 13363.36 cm^2.

25,000,000g/13,363.36cm^2 is our ratio to surface area. So for every square cm, Hulk can lift 1870.79 g per square cm. That's our factor. We just need to find his surface area for his "small" cube.

Scale it down to the small size.

7.62 cm has to be turned into a cube, as well. Since we figured out density and mass, we can figure out the rest.

M = ((b/a)^3)*m

((7.62cm/457cm)^3) * 4633100.7g = 21.5g

Lil' Hulk weighs 21.5g. How cute. 😊

Now that we know his little mass, we can use our guess on density to find his little volume: 21.5g/3g/cm^3 = 7.2 cm^3

Cube root that to find one side of his small cube: 1.931cm

ALMOST THERE!!!!

Square that one side to find the surface area of our small cube (I could have squared rooted our volume to find the surface area, but that's a bit confusing to follow for non-nerds, so I just skipped that short-cut, in both instances, and went for just one side so you could see the squaring happen):

3.73cm^2

Now we just apply our ratio and THEN subtract our mass from that product to find how much he could lift in the SAME manner he did against the tank:

1870.79 * 3.73 = 6978 grams. Subtract 21.5 g from that and it's 6957. OR... about 7 kilograms.

Before people freakout and say that isn't a lot of weight, that's absurdly much more than most bugs can lift that are larger.

Do a lifting to mass ratio for both sizes:

Big Hulk could lift 5.6 times his own body mass in the tank turret throwing feat while at his large size.

Now compare that to his small size: He has a mass of 21.5g and he can lift 6957 grams. Add those two together and divide it by his little mass to find how many times his body mass he can lift:

325.56 times his own body mass. A huge difference.

Conclusion:

Hulk can throw a 21 tonne turret many miles. Let's just say, for good measure (pun intended), it was 5 miles which is 8 km.

Scale that down. We know his little size is 7.62 cm. His big size is 457cm. Divide 7.62 by 457 to get your factor on distance: .133 km OR 133 meters. Hulk can throw something that weighs 7 kg 133 meters. That's STILL more than an olympic athlete can throw the same mass.

The olympic shot put weighs ABOUT 7 kg. It weighs 7.26 kg, so slightly more than the scaled down mass Hulk can throw.

So Hulk is MUCH stronger than a peak human (we are talking the world record holder for the shot put...and some consider that "superhuman" as the guy who set the record is a one out of a million in genetics and skills AND he took illegal substances...so really, his record is superhuman.)

So put someone who is well beyond superhuman in strength against a small human. This tiny Hulk will be able to exert forces much greater than a human on a much smaller area (much more PSI). Hulk could easily tear mini-me apart...LITERALLY.

Dude, he tossed an entire Abrams A1M1 Tank, that's 65-70 tons.

YouTube video

FF to 1:37

7vOlD304MZs&feature=related

/thread.

Same thing happened to Pym in The Ultimate Avengers. He grabbed Hulk in his hand; Hulk ****ed his shit up.

Originally posted by Robtard
Same thing happened to Pym in The Ultimate Avengers. He grabbed Hulk in his hand; Hulk ****ed his shit up.

I just watched that vid and I thought itwas the turret he throw.

NOPE...it was the whole tank.

I COULD go back over everything and change the numbers, but 21 tonnes should be more than sufficient enough to make the point.

If you want to go back over and change the numbers for a full sized M1A1 Abrams with a mass of 57200 kg, be my guest.

I "measured" the flight time of the tank and it's about 5 seconds.

Simply physics to figure out the distance thrown if the flight time was 5 seconds.

t = ((2^(1/2)) * v)/g

We know g...gravity

g = 9.80m/s2

5 = ((2^(1/2)) * v)/9.8m/s2

5*9.8m/s2 = (2^(1/2)) * v)

5*9.8m/s2 = (2^(1/2)) * v)

49 = 1.41*v

v = 34.65 m/s

We need v for this next part:

We will then use the standard 30 degrees angle of projection for our cosine portion.

t = d/(v*cos 30)

5 = d/(34.65 * cos 30)

5*29.83 = d

149.17 meters.

Is that right?

Maybe. That looks a bit short by about 150 meters. I figured out why, as well: his angle was much lower than 30 degrees: it was probably closer to 15 degrees.

5 = d/(34.65 * cos 15)

167.35 m

That's better, but still not quite right.

The dune he threw it into was a bit higher than where he threw it from so that's probably taking off a bit of the distance...maybe 10-20 meters, at the most.

Originally, when I saw that movie, I thought he threw it well over the "dune mountains" out of sight. So I thought it was about 5 miles rather than a tenth of a mile.

Hulk raped a 100 foot tall man. He rapes here.

Thanks for crunching the data, DDM.

It looks a lot further than a 10th of a mile, imo, going by how small the tank looks by comparison.

http://imageshack.us/f/121/hulktoss.png/

double post

Too bad Hulk rips off Mini Me's arm and beats him to death with it.

Originally posted by Rogue Jedi
Too bad Hulk rips off Mini Me's arm and beats him to death with it.

I don't think anyone is arguing that Hulk would lose here anymore.

Originally posted by dadudemon
I just watched that vid and I thought itwas the turret he throw.

NOPE...it was the whole tank.

I COULD go back over everything and change the numbers, but 21 tonnes should be more than sufficient enough to make the point.

If you want to go back over and change the numbers for a full sized M1A1 Abrams with a mass of 57200 kg, be my guest.

I "measured" the flight time of the tank and it's about 5 seconds.

Simply physics to figure out the distance thrown if the flight time was 5 seconds.

t = ((2^(1/2)) * v)/g

We know g...gravity

g = 9.80m/s2

5 = ((2^(1/2)) * v)/9.8m/s2

5*9.8m/s2 = (2^(1/2)) * v)

5*9.8m/s2 = (2^(1/2)) * v)

49 = 1.41*v

v = 34.65 m/s

We need v for this next part:

We will then use the standard 30 degrees angle of projection for our cosine portion.

t = d/(v*cos 30)

5 = d/(34.65 * cos 30)

5*29.83 = d

149.17 meters.

Is that right?

Maybe. That looks a bit short by about 150 meters. I figured out why, as well: his angle was much lower than 30 degrees: it was probably closer to 15 degrees.

5 = d/(34.65 * cos 15)

167.35 m

That's better, but still not quite right.

The dune he threw it into was a bit higher than where he threw it from so that's probably taking off a bit of the distance...maybe 10-20 meters, at the most.

Originally, when I saw that movie, I thought he threw it well over the "dune mountains" out of sight. So I thought it was about 5 miles rather than a tenth of a mile.

All that stuff and Hulk grabs mini me's throat and breaks it.

Dadudemon: I appreciate your work on this. I had a couple of comments: First, your mass for a 3 inch hulk was 21.5 grams. That is about 3/4 of an ounce. That kind of threw a red flag for me cuz you assumed that he is 3X as dense as a human (and I saw you used 1 g per cubic centimeter for a human which I'm sure is very close since that is the density of water). I have right in front of me a small Tylenol bottle that is about 2 inches tall, has 12 grams in the bottle, plus the weight of the bottle is unknown. I am sure that if we filled the empty spaces up with water I could easity get it up for over 28.4 grams (one ounce equivalent). It may be more like 1.5 ounces, I am not sure.
I bet a 3 inch hulk would weigh more than that given 3g/cc density, although I am not sure if that 3 g/cc is even accurate to begin with.

Also, about mini-hulk lifting 15 kg--two cats could do that. I believe you greatly underestimated his strength by factors of 10's to begin with. We need to go from lifting 21 tons (just the turret), to 65 tons as mentioned, then we need to figure how strong he would have to be to accelerate that type of weight like he did (Also, I know you used the 5 second acceleration math to determine distance, but in the movie it was clearly thrown further than what you figured). I believe his strength would be somewhere in the hundreds of tons. He and those dogs were breaking off large redwood branches, and he broke out of that underground base by shearing large metal bolts to knock that big metal hatch door off, etc. You had him lifting something like 5-6X his bodyweight when he can probably do a hundred or even a thousand--he climbed out of being buried by giant boulders. If he ever did had trouble lifting something, I think it was only cuz he could not get his body under it and therefore did not have the leverage to lift it.
And look at how far he can jump with his mass. His legs can probably produce force in the thousands of tons.
So I say take that 15 kg X 40-50 or so and that would be his lifting ability. And that may be underestimating it.

Thnk about it this way: If a 3 inch hulk could only lift 15 kg, you could keep him trapped in a small wood box (possibly, for awhile at least). Could you keep the movie hulk trapped in a wood box with even very thick wood? Heck no. How so could you keep a little hulk who is proportionately much, much stronger from punching through the same type of material when the surface area to puncture is very tiny and easier to do?

Also, to determine "scaling strength", I believe a pretty simple method works well: You just need to know two things:
1. Height difference between the two
2. How to figure the area of a circle: Pi X radius squared

Our muscles are more or less circles in the cross section. If Hulk gets 10 X shorter, his muscles get 10X less in radius (or diameter since radius is 1/2 diameter). So just figure the new cross section.

Since the muscle's strength is related to the cross section, the cross section will give you the proportionate strength by dividing the "Big Hulk" cross section by the "Mini Hulk" cross section.

I'm too lazy to do any figuring but I think it should be pretty easy given going from a 15 ft Hulk (15 ft X 12 inches per foot = 180 inches) to a 3 inch Hulk....ok I actually have a calculator here....
So that is 60X as tall as Mini Hulk, so proportionately all muscles will have 60X smaller diameter/radius...

EDIT: you can cancle Pi off of both sides, and I used 1/2 diameter instead of just saying "radius". But take the 1/2 off if you want also, and the answer is the same. We are just canceling numbers off both sides of an equation basically.

1/2 X 60 squared = 1/2 X 3,600 = 1800
Now for Mini Hulk: 1/2 X 1 squared = 1/2 X 1 = 0.5
(I repeated this with a couple other numbers besides "60 and 1", such as "30 and 0.5" and got the same answer that is explained below so this should be correct)

1,800 is 3,600 times stronger than 0.5 so Mini Hulk should be 3,600 times weaker, or 0.000277777 times as strong, or 0.027777 percent as strong. This is very very weak compared to his starting point, but his weight will have decreased by a much larger factor so he is still stronger for his size.

Of course he will lift things in a much shorter range of motion, doing much less work (force X distance). I believe that if figure total work done by both Hulks, the difference will be proportional to bidyweight difference since the longer distance helps Big Hulk "catch up" compared to his weaker force production proportionately.

This math was pretty easy and did not require any logarithmic stuff which you will need to figure mass difference when changing height. I will leave that up to you! I don't have a fancy calculator anymore although I am sure there are online calculators to make it easy.

Originally posted by K-Dog
Dadudemon: I appreciate your work on this. I had a couple of comments: First, your mass for a 3 inch hulk was 21.5 grams. That is about 3/4 of an ounce. That kind of threw a red flag for me cuz you assumed that he is 3X as dense as a human (and I saw you used 1 g per cubic centimeter for a human which I'm sure is very close since that is the density of water). I have right in front of me a small Tylenol bottle that is about 2 inches tall, has 12 grams in the bottle, plus the weight of the bottle is unknown. I am sure that if we filled the empty spaces up with water I could easity get it up for over 28.4 grams (one ounce equivalent). It may be more like 1.5 ounces, I am not sure.
I bet a 3 inch hulk would weigh more than that given 3g/cc density, although I am not sure if that 3 g/cc is even accurate to begin with.

It's not. It's an estimate that is probably close within 1 g/cm^3.

It's possible that he's more dense.

It's possible that he's only 2g/cm^3.

The point is to just give us an estimate within reason. He's obviously more dense than a regular human or even a rhino (rhinos are denser than most mammals) due to how durable his flesh is and how the tanks moved when he charged into it.

Keep in mind that we are dealing with a 3 inch tall version of Hulk.

It's possible I messed up somewhere in my math and 21 grams is too light. However, the formulas I used are not wrong. Feel free to check over my work and tell me if I made a simple arithmetic error.

However, it does not really matter in the scheme of things because you're just going to subtract that mass from the total mass he can lift and it is like a drop of water in a pond of water.

Originally posted by K-Dog
Also, about mini-hulk lifting 15 kg--two cats could do that. I believe you greatly underestimated his strength by factors of 10's to begin with.

I don't think you read my posts, then.

This was never about his maximum strength, this was about replicating, on scale, a feat he performed in the movie. That's quite clearly outlined in the post.

Estimating his high strength would be impossible since it's "limitless". We just want to give an estimate for comparison. If the estimate shows a far greater level of strength than a Mini-Me could handle, then we could end the entire discussion.

If the estimate, once scaled down, did not approach adequate levels, we would have to search for a better strength feat OR given up on the discussion.

Originally posted by K-Dog
We need to go from lifting 21 tons (just the turret), to 65 tons as mentioned,

This is not necessary, as I've already outlined.

And it's tonnes, not tons. This is important because a tonne has more mass than a ton (lol).

Originally posted by K-Dog
then we need to figure how strong he would have to be to accelerate that type of weight like he did (Also, I know you used the 5 second acceleration math to determine distance, but in the movie it was clearly thrown further than what you figured).

You say "clearly" but it's actually not clear. He throws it up at an angle, it has a travel time and an arch. That can be very easily mapped with highschool projectile physics with only an estimate on the initial angle. I first estimated it at 30 degrees. That didn't give us the desired results.

So I dropped it down to 15, despite the fact that it looks greater than 15.

That still did not generate the proper results.

Conclusion: either the tank had significant aerodynamic properties (not true due to it's shape and density) or the animation team fudged some of the physics in their physics engine (the correct answer.)

I'm not sure why they did that because they already spent a large sum of money for their software which already has "earthly" physics built in.

Well...actually...I DO know why they did that: they didn't want to wait the 12 seconds (guess) for it to fly through the air and land so they sped it up making gravity seem higher in that one particular shot.

Originally posted by K-Dog
I believe his strength would be somewhere in the hundreds of tons.

By far, actually. Based on the tank throwing feat, alone, it would easily be over 1000 tonnes.

Originally posted by K-Dog
He and those dogs were breaking off large redwood branches, and he broke out of that underground base by shearing large metal bolts to knock that big metal hatch door off, etc. You had him lifting something like 5-6X his bodyweight when he can probably do a hundred or even a thousand--

This was never about his maximum strength, this was about replicating, on scale, a feat he performed in the movie. That's quite clearly outlined in the post.

Originally posted by K-Dog
he climbed out of being buried by giant boulders. If he ever did had trouble lifting something, I think it was only cuz he could not get his body under it and therefore did not have the leverage to lift it.

I think it's more to do with the fact that he was phased a bit than not getting "purchase". 😄

Originally posted by K-Dog
And look at how far he can jump with his mass. His legs can probably produce force in the thousands of tons.

I agree. That feat, however, would be far more complicated to calculate than scaling down his throwing feat.

Again, we only need to establish a simply strength feat for congruency purposes. If the strength produced is adequate enough to make Mini-Me look like a weakling, then we do NOT need to go crazy and start estimating a whole bunch of his feats: that's unnecessary.

As your professor will tell you in college: K.I.S.S. - Keep it simple stupid. If you go too far or use something more complicated than necessary, you may not be able to complete a project on time and get docked points for it. That's obviously a bad thing.

Originally posted by K-Dog
So I say take that 15 kg X 40-50 or so and that would be his lifting ability. And that may be underestimating it.

It was 7 kg, btw, not 15.

For the purposes of the thread, we only needed to prove that his strength was significantly beyond that of Mini-Me.

I showed that the tank throwing feat has Hulk throwing something quite far: significantly into the Superhuman levels.

I was wrong on my distance because I thought he throw it over the large mountainous sand dune, but it threw it at the base. It LOOKS to be about 1 km instead of 8. The math, using regular physics, does not add up for how far the distance APPEARS.

Well...I COULD use some "light" and distance physics to determine the distance thrown (the tank gets smaller and smaller based on the distance from the observer...so we could actually estimate the tank's distance based on that...and it would be quite accurate if we did it down to the pixel...in fact, it would be more accurate, doing it that way, than if we could come within 2-3 degrees of the angle of projection.)

But, it's not necessary. Remember: KISS.

We only need to show that Hulk is far stronger than Mini-Me. We already know...even just scaling the jumps themselves, that Hulk is far more agile than Mini-Me. Mix in his superhuman reflexes and the only way Mini-Me would win this fight is if he was significantly stronger than Hulk. So we only needed to prove that wasn't the case. Nothing more.

Originally posted by K-Dog
Thnk about it this way: If a 3 inch hulk could only lift 15 kg, you could keep him trapped in a small wood box (possibly, for awhile at least). Could you keep the movie hulk trapped in a wood box with even very thick wood? Heck no. How so could you keep a little hulk who is proportionately much, much stronger from punching through the same type of material when the surface area to puncture is very tiny and easier to do?

You're confusing a really far throwing feat for "maximum lifting strength." That's not the case.

About the box: if such a small creature could exert that much force like he did for the tank throw, the amount of acute forces he could generate on the box would be astronomical for such a little dude. He would easily punch right through a wood box (depending on how thick it was.) If he could get leverage (say, pushing on top of the box), he could easily push apart a box from the glue/nails/screws. In fact, his strength would be so great that he could just dig his way out of the box: the wood would be almost like splintery play-dough for Hulk.

Ok, yes i was thinking "about 15 lbs" when I read 7 kg, and I must have kept that number in my head.
Well anyway, if we use 7 kg / 15ish lbs as his lifting ability and use that alone, then the fight is not really a guaranteed win for Hulk. Even a small man like mini-me could probably hurt a creature than can only lift 7 kg by stepping on them. He probably weighs 3X that much. And in saying so, I believe that for mini-Hulk to easily win a majority, he needs a little bit more full credit for his feats calculated to scale. So even if we raise your numbers from lifting the turret to lifting the whole tank, his strength goes up about 3X (and therefore I assume his durability also) and it makes it a sure win.

And you did a good job on the calculations and figuring the throwing distance and stuff and I think you as well as several others understood from the beginning that the distance/time didn't add up just by watching the film. I actually thought it "floated" more slowly than it should have, but yet it actually went further and therefore "faster" than it should have.

Originally posted by K-Dog
Ok, yes i was thinking "about 15 lbs" when I read 7 kg, and I must have kept that number in my head.
Well anyway, if we use 7 kg / 15ish lbs as his lifting ability and use that alone, then the fight is not really a guaranteed win for Hulk.

It is because:

"Again, we only need to establish a simple strength feat for congruency purposes. If the strength produced is adequate enough to make Mini-Me look like a weakling, then we do NOT need to go crazy and start estimating a whole bunch of his feats: that's unnecessary."

Why is it unncessary? Because:

"We already know...even just scaling the jumps themselves, that Hulk is far more agile than Mini-Me. Mix in his superhuman reflexes and the only way Mini-Me would win this fight is if he was significantly stronger than Hulk."

Because Mini-Me is slower, has poorer reflexes, is not as durable, etc. Mini-Me has to edge out Hulk in strength and Hulk has to be weaker than Mini-Me. Why? If Hulk is weaker, he will not produce enough force to harm Mini-Me that much with his tiny fists.

If he's about as strong as Mini-Me, he could actually start punching holes in Mini-Me's flash.

If he's significantly stronger, which he is because he can throw a 7kg shotput further than any human (making him superhuman in strength, using ONLY one feat, alone), he could literally rip Mini-Me's flesh right off the bones.

Originally posted by K-Dog
Even a small man like mini-me could probably hurt a creature than can only lift 7 kg by stepping on them.

You're going about it all wrong. It's not "lifting" it's throwing 7kg dozens of meters.

Originally posted by K-Dog
He probably weighs 3X that much.

Which means Hulk will throw Mini-Me...20-40 meters instead of 100+. 😄

Originally posted by K-Dog
And in saying so, I believe that for mini-Hulk to easily win a majority, he needs a little bit more full credit for his feats calculated to scale.

No he doesn't: what I've provided is already waaaaaay more than adequate enough ESPECIALLY if you consider that I underestimated the top-end mass by almost 1/3.

Originally posted by K-Dog
So even if we raise your numbers from lifting the turret to lifting the whole tank, his strength goes up about 3X (and therefore I assume his durability also) and it makes it a sure win.

I disagree: I don't think the math works out like that since we are dealing in 3 different dimensions: linear mass, cross-sectional area, and volume.

It's not as smooth as a linear relationship because we are square rooting and cube rooting the numbers on each end.

Originally posted by K-Dog
And you did a good job on the calculations and figuring the throwing distance and stuff and I think you as well as several others understood from the beginning that the distance/time didn't add up just by watching the film. I actually thought it "floated" more slowly than it should have, but yet it actually went further and therefore "faster" than it should have.

Thanks, man. I feel under-appreciated, at times. 🙁

lol

Edit - Also, yeah, I thought you meant 15 lbs and I even used 15 at one point in my last reply because I thought that's what you meant...but I wasn't certain so I forgot to edit my post to say 7kg.

quote: (post)
Originally posted by K-Dog
So even if we raise your numbers from lifting the turret to lifting the whole tank, his strength goes up about 3X (and therefore I assume his durability also) and it makes it a sure win.)))))

I disagree: I don't think the math works out like that since we are dealing in 3 different dimensions: linear mass, cross-sectional area, and volume.

It's not as smooth as a linear relationship because we are square rooting and cube rooting the numbers on each end.))))

I was just meaning that you could just take all your figures for the turret and multiply then X about 3 since the Hulk clearly threw the entire tank.

On a side note, if we want to determine how far he could throw Mini-me, I do believe the total kinetic energy he is able to produce will be directly linearly proportional to his weight/mass difference. Tell me if you think I am wrong, but I believe the work (force X distance) is proportional in the same way since work is measured in energy.

So figure the energy required to throw the 65-70 tonne tank whatever distance we think it went, and divide that by the ratio of weight of big hulk : weight of small hulk. That's how much KE he (little hulk) can make. Then we need to know Vern Troyer's weight and we are off to the races!
Vern isn't going to know what hit him!
But then.....little hulk is too small to counterbalance Vern spinning around like he threw the tank....he may just have to shot-put him!

Originally posted by K-Dog
I was just meaning that you could just take all your figures for the turret and multiply then X about 3 since the Hulk clearly threw the entire tank.

And what I was saying is: it doesn't work out quite like that due to the relationship of cross-sectional area.

Originally posted by K-Dog
On a side note, if we want to determine how far he could throw Mini-me, I do believe the total kinetic energy he is able to produce will be directly linearly proportional to his weight/mass difference. Tell me if you think I am wrong, but I believe the work (force X distance) is proportional in the same way since work is measured in energy.

Same as above: doesn't work out quite like that due to the relationship of cross-sectional area.

You actually get stronger the smaller you get in relation to your own mass (assuming we have an adjustable shrink ray, of course. 😄)

So it would be geometric relationship, not a linear one (we know this, actually).

Originally posted by K-Dog
So figure the energy required to throw the 65-70 tonne tank whatever distance we think it went, and divide that by the ratio of weight of big hulk : weight of small hulk. That's how much KE he (little hulk) can make. Then we need to know Vern Troyer's weight and we are off to the races!

Not quite for reasons I outlined above.

Also, awesome correction on the "tonne" reference. 👆
I never correct anyone on anything as long as we can understand but we have multiple European posters here and it just makes it easier on them since it is our own stupid "Yank" measurement system that's the problem. (I figure that's it our fault for using the system that hardly anyone uses...so we should be polite enough adjust to to the rest of the world.)

Originally posted by K-Dog
Vern isn't going to know what hit him!
But then.....little hulk is too small to counterbalance Vern spinning around like he threw the tank....he may just have to shot-put him!

I looked up, online, and saw that Verne weighs between 40-55 lbs...but none of those are credible.

So that's between 2-3 times heavier than the tank being shrunk down. So, yeah, it might be too heavy to throw like that.