Batman Vs. U.S. Air Force pilot (Aerial dogfight)

Started by The Transporter1 pages

Batman Vs. U.S. Air Force pilot (Aerial dogfight)

Batman piloting the current Batplane ( Wayne Aviation SlipStream) vs. pilot in a F-22 Raptor. The Batplane is equipped with any and all armament used by any previous Batplanes. Dogfight takes place at 0900 hours under optimal weather conditions over Fiji. Full visibility.

Rules: No holding back, neither pilot is to eject from their aircraft at any time, No outside help (i.e. control tower, radio communications, or passangers, ally intervention), no suicide (no kamikaze, flares are limited to 6,).

*Stats:

Batplane:
Height: 14.5 ft.
Length: 57.7 ft.
Wingspan: 47.6 ft.
Service Ceiling: 60,000 ft
Maximum Speed: 4,400 mph
Range: 2,486 n m i
Armament: Any and all weapons utilized by any Batplane model.
The wings are protected by a bleed-air anti-icing system.

F-22 Raptor:
Height: 16 ft 8 in
Length: 62 ft 1 in (18.90 m)
Wingspan: 44 ft 6 in (13.56 m)
Service Ceiling: 65, 000 ft
Maximum Speed: 1,500 mph
Range: 1,840 n m i
Armament (Air to air armament only):
Guns: 1× 20 mm (0.787 in) M61A2 Vulcan 6-barreled gatling cannon in
6× AIM-120 AMRAAM
2× AIM-9 Sidewinder

Batplane.

The tech Batman employs on a regular basis is beyond what's feasible by real world military tech.

Batman pulls some plot bs such as a super EMP and punks the pilot.

Batman wins without ever using the batplane.

Speed alone crushed F-22 no question... Batman could fly in circles and wait for the pilot to run out of gas. Everyone knows that the Batplane has a fuel efficiency greater than 15000000000000%