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Immortal Hulk vs. Yoda
Started by: LordGod

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LordGod
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Immortal Hulk vs. Yoda

Most thought Hulk would wreck Vader, so would Yoda do any better?


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Old Post Feb 10th, 2020 10:33 PM
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Galan007
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Old Post Feb 10th, 2020 10:45 PM
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StiltmanFTW
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Hulk is greener.


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Old Post Feb 10th, 2020 10:47 PM
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Galan007
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Hulk is the greenest there is. thumb up


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Old Post Feb 10th, 2020 10:50 PM
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Disturbedrogue
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Immortal Hulk

Old Post Feb 11th, 2020 09:23 PM
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Sin I AM
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Has anyone tried to grabbing Hulk before?


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Old Post Feb 11th, 2020 09:28 PM
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Eon Blue
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Yoda wins.


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Old Post Feb 11th, 2020 11:07 PM
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Damborgson
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quote: (post)
Originally posted by Sin I AM
Has anyone tried to grabbing Hulk before?


Carver tried to grab Hulk once...results were, mixed....


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Old Post Feb 11th, 2020 11:11 PM
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StiltmanFTW
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laughing out loud laughing out loud laughing out loud


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Old Post Feb 11th, 2020 11:24 PM
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Magnon
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Yoda could throw Hulk into space with such an acceleration that, by the time Hulk realized what was happening, the distance between him and the planet they were on would already be equal to several planetary radii.

Lets do some maths, based on Yoda's mountain-lifting feat. Assume the gravitational acceleration on that planet was 1 g, the mass of the mountain 2E14 kg, and the mass of Hulk 600 kg.

CALCULATION: (you can skip this, and go directly to RESULTS below)
The force F (actual physical force, not the Force) required to lift the mountain equals 1.96E15 newtons. Such a force when applied on Hulk will accelerate him to relativistic speeds in a fraction of a second, so a special-relativistic analysis is required. In relativity, the relation between (proper) force F and proper acceleration α is given by (where m = Hulk's mass) :

F = mα (eqn 1)

This resembles the famous Newton's second law. The proper acceleration is related to coordinate acceleration "a" by

α = γ^3 a

where γ is the Lorentz factor. Substituting this into (eqn 1) and integrating yields the speed v (of Hulk) at time t:

v = c / sqrt[1 + (mc/Ft)^2] (eqn 2)

Here, c is the speed of light. Integration of (eqn 2) with respect to t yields the distance d traveled (by Hulk) in time t.

RESULTS:

In the table below, t is the time from the start of Yoda's force-push on Hulk, v is Hulk's speed at time t due to the force-push, and d is the distance traveled by Hulk at time t.
code:
t (seconds) v (in units where c = 1.00) d (in units where Earth's diameter = 1.00) ----------------------------------------------------------------------------------------- 0 0 0 0.0001 0.737 0.001 0.001 0.996 0.022 0.01 0.99996 0.23 0.1 ~1 2.4 1 ~1 24

Within one second, Hulk would be 24 Earth's diameters away from the planet they were fighting on. Now that's BFR!

Old Post Feb 11th, 2020 11:28 PM
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StiltmanFTW
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Hello, h1a8


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Old Post Feb 12th, 2020 12:14 AM
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Proper_
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This thread is laughable. Hulk blitzes and one shots

Old Post Feb 12th, 2020 06:24 AM
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MrMind
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quote: (post)
Originally posted by Magnon
Yoda could throw Hulk into space with such an acceleration that, by the time Hulk realized what was happening, the distance between him and the planet they were on would already be equal to several planetary radii.

Lets do some maths, based on Yoda's mountain-lifting feat. Assume the gravitational acceleration on that planet was 1 g, the mass of the mountain 2E14 kg, and the mass of Hulk 600 kg.

CALCULATION: (you can skip this, and go directly to RESULTS below)
The force F (actual physical force, not the Force) required to lift the mountain equals 1.96E15 newtons. Such a force when applied on Hulk will accelerate him to relativistic speeds in a fraction of a second, so a special-relativistic analysis is required. In relativity, the relation between (proper) force F and proper acceleration α is given by (where m = Hulk's mass) :

F = mα (eqn 1)

This resembles the famous Newton's second law. The proper acceleration is related to coordinate acceleration "a" by

α = γ^3 a

where γ is the Lorentz factor. Substituting this into (eqn 1) and integrating yields the speed v (of Hulk) at time t:

v = c / sqrt[1 + (mc/Ft)^2] (eqn 2)

Here, c is the speed of light. Integration of (eqn 2) with respect to t yields the distance d traveled (by Hulk) in time t.

RESULTS:

In the table below, t is the time from the start of Yoda's force-push on Hulk, v is Hulk's speed at time t due to the force-push, and d is the distance traveled by Hulk at time t.
code:
t (seconds) v (in units where c = 1.00) d (in units where Earth's diameter = 1.00) ----------------------------------------------------------------------------------------- 0 0 0 0.0001 0.737 0.001 0.001 0.996 0.022 0.01 0.99996 0.23 0.1 ~1 2.4 1 ~1 24

Within one second, Hulk would be 24 Earth's diameters away from the planet they were fighting on. Now that's BFR!


I love it


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Old Post Feb 12th, 2020 07:45 AM
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spetznaz
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quote: (post)
Originally posted by Magnon
Yoda could throw Hulk into space with such an acceleration that, by the time Hulk realized what was happening, the distance between him and the planet they were on would already be equal to several planetary radii.

Lets do some maths, based on Yoda's mountain-lifting feat. Assume the gravitational acceleration on that planet was 1 g, the mass of the mountain 2E14 kg, and the mass of Hulk 600 kg.

CALCULATION: (you can skip this, and go directly to RESULTS below)
The force F (actual physical force, not the Force) required to lift the mountain equals 1.96E15 newtons. Such a force when applied on Hulk will accelerate him to relativistic speeds in a fraction of a second, so a special-relativistic analysis is required. In relativity, the relation between (proper) force F and proper acceleration α is given by (where m = Hulk's mass) :

F = mα (eqn 1)

This resembles the famous Newton's second law. The proper acceleration is related to coordinate acceleration "a" by

α = γ^3 a

where γ is the Lorentz factor. Substituting this into (eqn 1) and integrating yields the speed v (of Hulk) at time t:

v = c / sqrt[1 + (mc/Ft)^2] (eqn 2)

Here, c is the speed of light. Integration of (eqn 2) with respect to t yields the distance d traveled (by Hulk) in time t.

RESULTS:

In the table below, t is the time from the start of Yoda's force-push on Hulk, v is Hulk's speed at time t due to the force-push, and d is the distance traveled by Hulk at time t.
code:
t (seconds) v (in units where c = 1.00) d (in units where Earth's diameter = 1.00) ----------------------------------------------------------------------------------------- 0 0 0 0.0001 0.737 0.001 0.001 0.996 0.022 0.01 0.99996 0.23 0.1 ~1 2.4 1 ~1 24

Within one second, Hulk would be 24 Earth's diameters away from the planet they were fighting on. Now that's BFR!



The Force is strooooong in you!


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Old Post Feb 12th, 2020 12:12 PM
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cdtm
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Re: Immortal Hulk vs. Yoda

quote: (post)
Originally posted by LordGod
Most thought Hulk would wreck Vader, so would Yoda do any better?



By most, you mean two?


No one who really counted thought this. smile


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Old Post Feb 12th, 2020 02:19 PM
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LordGod
Shaper of Reality

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Well I mean there's no one arguing for Hulk here. Is Yoda really that far beyond Darth vader?


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Old Post Feb 12th, 2020 07:17 PM
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DarkSaint85
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quote: (post)
Originally posted by Sin I AM
Has anyone tried to grabbing Hulk before?


Internally? I once asked that in a Mate Grey thread, and Bran went on a rant against me lol.

I don't think he can fight against someone grabbing his heart and lifting it, tbh.


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Old Post Feb 13th, 2020 05:50 PM
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StiltmanFTW
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Was that in the Nate vs. Hulk thread?

Star Wars characters were never meant to be taking on threats such as the Hulk.


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Old Post Feb 13th, 2020 06:00 PM
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Galan007
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quote: (post)
Originally posted by LordGod
Is Yoda really that far beyond Darth vader?
TK-wise, Vader can likely approach Yoda/Palpatine-level, but they're still superior.

...There's also the fact that Vader doesn't have a TK feat on par with hurling a mountain-sized creature to the ground, while also holding back an entire group of force-sensitives.

quote: (post)
Originally posted by StiltmanFTW
Star Wars characters were never meant to be taking on threats such as the Hulk.
And rightfully so. That kind of BS would ruin the franchise for me.


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Old Post Feb 13th, 2020 06:14 PM
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StiltmanFTW
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thumb up


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