Originally posted by Fëanor
PERVY POSTS!!!! WHY YOU[EDIT: DUE TO MATURE CONTENT AIMED AT MEMBER OF GOOD STANDING AND A BENEFIT TO THE COMMUNITY WHOSE ONLY DESIRE IS TO DO GOOD AND CHARITABLE CONTRIBUTION TO ALL THOSE LESS FORTUNATE THAN SAID MEMBERe.g discos[colour=red]][/color]Last edited by Shadowy_Exa today at 15:99pm
😆 😱 😆 😱 😆
i started the only lasting Fad
the mock discos fad 😛
and soon---very soon, AD Skinner will join me!
Originally posted by I am a Sock
oops, made an error. hold on.Step 1: -1/1 = 1/-1
Step 2: Taking the square root of both sides: sqrt(-1/1)=sqrt(1/-1)
Step 3: Simplifying: sqrt(-1)/sqrt(1)=sqrt(1)/sqrt(-1)
Step 4: In other words, i/1 = 1/i.
Step 5: Therefore, i / 2 = 1 / (2i),
Step 6: i/2 + 3/(2i) = 1/(2i) + 3/(2i),
Step 7: i (i/2 + 3/(2i) ) = i ( 1/(2i) + 3/(2i) ),
Step 8: i^2/2 + (3i)/(2i) = i/(2i)+(3i)/(2i)
Step 9: (-1)/2 + 3/2 = 1/2 + 3/2,
Step 10: and this shows that 1=2.
fixed now find the error
This one?