Originally posted by jollyjim311
Mace would beat 10 average Jedi, seeing as how Sidious beat three very powerful Jedi in a few seconds while focusing mainly on Mace.In Battlefront 2 there's no way to kill a normal rancor. Does that mean they're unbeatable? No, let's be realistic. Who here has actually read Shatterpoint? Who here has seen the Clone Wars cartoons?
That logic does not work unfortunatley. Let's say you got one person with half Obi-Wan's skill, and they face off. Obi wins.
Then you have two persons of Obi-Wan's skill, does that mean they stalemate? Hardly, seeing how they are two persons, who could easily find an opening somewhere, and because of their numbers, push him back alot more, even make him change his strategy.
Point is, that if there were 10 jedi facing of Sidious, he wouldn't kill them as quickly as 3 powerful ones, because he wouldn't really have the room to. They could easily surround him and subdue him, the entire fight is not the same at all.
And although Mace COULD probably defeat them through tactics, the entire fight is different. You cannot go "Sids defeat three with super ease, so he beats 10 with some difficult", because they way you put your offense has to be completley different. And the room Sids fought those 3 jedi in was actually to his advantage, they had no room to step beside eachother or swing out wildly. And after all, Sidious and Mace do not have the same styles, strategies nor personalities, so it doesn't apply anyway.
I'm not denying Mace can have a chance against 10 jedi, but I do not support your way of thinking, nor support that he WILL beat 10 jedi.
And I never said that the Mutant Rancor was freaking invinsible, I was countering what Vader said when he replied "I killed the rancor before". In the level, you cannot kill it without doing what you are supposed to do, Jaden is not capable. Never did I say it couldn't die, at least that is not what I meant at all. I even said I thought Mace would win this after a tough fight.