Originally posted by Violent2Dope😐
Well, technically he's right. Pulling something against the gravitational pull of sumthin as large as the sun would be much harder than pulling it without gravity.
Basic physics...
If you lift your iPod, you aren't lifting hundreds of iPods.... the explanation he goes on to give says that multiplying the masses of the objects gives you how many of the objects you're lifting.
When you lift your iPod, do you lift the earth?
Originally posted by SaintSmurph
😐Basic physics...
If you lift your iPod, you aren't lifting hundreds of iPods.... the explanation he goes on to give says that multiplying the masses of the objects gives you how many of the objects you're lifting.
When you lift your iPod, do you lift the earth?
Originally posted by nvrbeenwthagirlCompletely irrelevant to why pulling one third of the earth = pulling hundreds of earths. Besides, by your logic, pulling the earth = pulling hundreds of suns.
THe ipod already has an established weight against the earth's gravity. If you were to pull that same ipon against the Sun's gravity, you'd be in some serious trouble. YOu'd have to be close enough to the sun for it to mean anything with an object so small, but you get the point.
It's Christmas, so I'm not gonna debate this with you any further. Needless to say, you need to go back to highschool.
Also, Merry Christmas all.
Originally posted by SaintSmurph
Completely irrelevant to why pulling one third of the earth = pulling hundreds of earths. Besides, by your logic, pulling the earth = pulling hundreds of suns.It's Christmas, so I'm not gonna debate this with you any further. Needless to say, you need to go back to highschool.
Also, Merry Christmas all.
Originally posted by DesaadIm just getting warmed up. Tomorrow Im off and Im just working out and dedicating a shitload of time to finally do this and do it right.
I'll be waaaiiitttting.
Im off to the gym right now and I wont be responding anymore with my own scans tonight but tomorrow its on.
Nobody ****s with Thanos on my watch.
Originally posted by nvrbeenwthagirlMoving the earth in weightless space WOULDN'T EVEN BE A STRENGTH FEAT.
Now, Moving the earth in weightless space towards the sun would be far easier than trying to pull the earth out of orbit against the sun's pull.
When people are talking about her moving a third of the earth with her strength, OBVIOUSLY it's assumed that it's in orbit around a sun.
Therefore saying that it takes the same strength to move a planet in orbit as it takes to move a hundred of the planets not in orbit is not only completely misleading (as planets are assumed to be in orbit for a strength feat, so Diana's feat is nothing more than a third of the earth), it's completely and utterly f*cking wrong.
Furthermore.
You seem to think that one must multiply the masses of the planets with a gravitational force between them. This, you said in the other thread, and have alluded to in this thread.
That's moronic.
Go back to highschool.
Originally posted by Violent2DopeI don't think you understand properly.
Well, technically he's right. Pulling something against the gravitational pull of sumthin as large as the sun would be much harder than pulling it without gravity.
He said that pulling 1/3rd of the Earth was like pulling a hundred Earths.
The earth has an established mass and thus an established weight in the gravity of the sun. So moving 1/3rd the earth is like moving 1/3rd of the earth. moving 1/3 of an object from where it IS at present will always be like moving 1/3 of an object from where it is at present. Moving 1/3 of an object from where it is at present will never be like moving a hundred of the object.
and the analogy with the ipod is valid
ipod=Earth
Earth=Sun
1.99066667 × 10^21 metric tons does not magically become 5.97200 × 10^23 metric tons
Yes, scientists at the university of washington estimated that the earth weighs 5.972 sextillion metric tons. So supposing that is accurate then 1/3rd of that would not magically become a hundred times that. And yes it already is in the gravitational well of the Sun, hence that's why that's what its orbiting. If it wasn't IN the gravitational well it ouldn't be orbiting it.
Originally posted by Creshosk
I don't think you understand properly.He said that pulling 1/3rd of the Earth was like pulling a hundred Earths.
The earth has an established mass and thus an established weight in the gravity of the sun. So moving 1/3rd the earth is like moving 1/3rd of the earth. moving 1/3 of an object from where it IS at present will always be like moving 1/3 of an object from where it is at present. Moving 1/3 of an object from where it is at present will never be like moving a hundred of the object.
and the analogy with the ipod is valid
ipod=Earth
Earth=Sun1.99066667 × 10^21 metric tons does not magically become 5.97200 × 10^23 metric tons
Yes, scientists at the university of washington estimated that the earth weighs 5.972 sextillion metric tons. So supposing that is accurate then 1/3rd of that would not magically become a hundred times that. And yes it already is in the gravitational well of the Sun, hence that's why that's what its orbiting. If it wasn't IN the gravitational well it ouldn't be orbiting it.
Scientist are weighting the earth of it's own accord. meaning they are using the mass of the earth, in conjunction with the earth's gravitational pull, to come up with a weight that can be understood with in the earth's gravitational pull. How if the Earth were Being Ulled out of orbit against the sun, One couldn't simply take the earth's weight as what is being pulled, One would have to factor in the gravitational pull of the sun, which thus creates an additional mass. The force that killed the dinosaurs didn't even rock the earth out of orbit. Kinda tells you what kinda force you are pulling against when you are moving the earth out of it's orbit. YOu aren't just pulling against the mass of the earth, but in relation to the hold that the sun has on it.