Most Impressive Strength Cheese Feats

Originally posted by celeyhyga17
Alright you mathletes.. Saw this on comicvine. How good are these calculations?

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(by killemall)
And Hyperion doesnt even need to stop the planet, if he even remotely slows down the rogue planet at that speed its not as hard to pull it off.

Lets see, what would it mean if Hyperion actually outright stopped the planet (I am not saying Hyperion did in fact stop the planet, he didnt, but how much power would it require to stop a planet).

Remember the planet is accelerating at 500,000 miles per hours but science requires you to used meters per seconds.

So thats 2,235,200 meters per seconds.

Lets assume the weight of the planet is represented as "Weight"

The Force at which the planet is being propelled is given by a simple equation F= m x acceleration

in this case its = 2,235,200 x Weight.

how much force would it require to stop the planet, at the very least just as much as its moving at, iin fact a little but higher.

But its force, how doe it translates to weight lifted.

Remember under earth's gravity, it takes 9 N to lift a kilogram, and hence in order to outright Stop the planet the amount of force involved is equivalient to lifting 2,235,200/ 9 = 248,355.55 times the weight.

In short, if Hyperion stopped the rogue planet outright, the feat would be equivalent to lifting 248 thousands times the weight of the said planet.

Remember we dont know how heavy the Rogue planet is, but it is still a planet, lets say its 1/1000 the time of Earth (honest it cant get any smaller.

Outright stopping the planet would still have been as impressive as lifting 248 times the weight of the earth.

Heck even if he slowed it down by 2%, instead of outright stop him, its still as impressive as lifting 5 planets together.

That assuming Earth is somehow 1000 times bigger than the rogue planet in question, and Hyperion only slowed the planet by 2%.

Hence if you are willing to look at it with a reasonable side, Hyperion feat is just as impressive, its just that we dont have numerical value unless you are telling me the planet is somehow more than 1/1000 the size of the Earth or Hyperion didnt even slow him down by 2%.

There is the caculation with extremely generous variable if you are interested.
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The guy has no clue what he is talking about... lol

But stopping the planet in a second (assuming it's 1/1000 the mass of the Earth) would take about 230 times the force to hold (not lift or move) the weight of the Earth.

Originally posted by ares834
The guy has no clue what he is talking about... lol

But stopping the planet in a second (assuming it's 1/1000 the mass of the Earth) would take about 230 times the force to hold (not lift or move) the weight of the Earth.

Originally posted by ares834
The guy has no clue what he is talking about... lol

But stopping the planet in a second (assuming it's 1/1000 the mass of the Earth) would take about 230 times the force to hold (not lift or move) the weight of the Earth.

"Stopping the planet" by itself does not imply how much energy is exerted, since that depends on the planet's velocity, so an unknown variable value being 230 smaller than a fixed value is pretty hilarious.

Originally posted by celeyhyga17
Alright you mathletes.. Saw this on comicvine. How good are these calculations?

Let's assume this is the smallest planet possible (to get a minimum figure). This means one of its requirements to be called a planet is that it still has to be large enough to achieve "hydrostatic equilibrium." In planetary terms, this means the body has to be large enough so that its gravity is strong enough to compress it into a sphere. An astronomically well-known example is Ceres. It is the largest asteroid known (in the belt between Mars and Jupiter), and represents the minimum "planetary size": about 600 miles in diameter (the reason Ceres is not considered a planet is because it fails to meet one of the three requirements established by the International Astronomical Union: Ceres has not cleared its orbital path of debris, ie, other asteroids; but I digress).

So: the Hyperion-targeted planet (henceforth, simply called, the Planet) has a mass (like Ceres) of 9x10^20 (900 billion billion) kg. And it is moving at 500,000 mph, or (roughly) 140 miles/sec, or about 225,000 meters/sec. We now have figures we can plug into K=1/2mv^2.

K = 1/2(9x10^20) x (225,000x225,000)
K = (4.5x10^20) x (5x10^10)
K = 22.5x10^30, or 2.25x10^31 joules

By comparison, Earth's kinetic orbital energy is 2.7x10^33 joules, or roughly 100x greater. As stated from the onset, Planet's stopping energy would be a minimum figure.

By another comparison, the Sun's annual energy output per second is 3.8x10^26 joules.

According to these calculations (I strongly advise someone check my figures), this means Hyperion put out about 100,000x the power of the Sun, each second, to stop that Planet (I'm assuming it would take an amount of power equivalent to its kinetic energy).

Essentially, between what it takes to blow up a planet, and/or stop it from moving: the lesson is, rocky worlds may be small compared to a star or gas giant, but there's still a god-awful amount of matter that has to be reckoned with, far more than its mere/comparative size would suggest. This also completely ignores tidal forces, any tectonic repercussions, loss of any atmosphere, etc. It also ignores the fact that a Superman-calibre/sized being pushing against a planet would be like a BB shooting through a cake, rather than a BB pushing the whole cake.

(Also, for those interested, google "orders of magnitude joules" to see where I got some of my figures from).

Originally posted by celeyhyga17
Please explain.

I'll just run through the "calc".

Force = mass * acceleration

So to stop the rouge planet you need to put a force on it which is dependent on time. When you hold up an object you have to apply a force equal to its weight. Weight = mass * acceleration of gravity. Acceleration of gravity on the surface of the earth is about 9.8 m/s so the "weight" of the Earth would be 9.8 Earth masses (although using Earth gravity there is weird).

You can use that same equation to figure out how much force to stop the rouge planet. It's traveling at 2,235,200 m/s so how much deceleration would it require to go from that speed to 0 m/s in a second (I have no clue how long it took Hyperion to stop it but it certainly seems longer than a second). Well the acceleration to do so would be rater obviously 2,235,200 m/s^2. So you take that number and multiply it by the mass of the Rouge Planet (which we assumed to be 1/1000 of the Earth for whatever reason) so that's 1/1000 Earth masses * 2,235,200 which comes out to be 2,235 Earth masses.

2,235 Earth masses/9.8 earth masses comes out to be a bit less than 230. So it takes roughly 230 times as much force.

But yeah, a lot of incorrect assumptions on my part. The mass of the planet is obviously far more than 1/1000 of the Earth. Hyperion also seemed to take a bit longer than a second. Regardless, the guy who initially did the calc had no clue what he was doing.

Originally posted by ares834
It's traveling at 2,235,200 m/s

Originally posted by ares834
so that's 1/1000 Earth masses * 2,235,200 which comes out to be 2,235 Earth masses.

Originally posted by Mindship
According to these calculations (I strongly advise someone check my figures)

Originally posted by Philosophía
Check again.

Ah. I was to lazy to convert MPH to M/s and assumed he did so correctly. 😛

Originally posted by Mindship
By comparison, Earth's kinetic orbital energy is 2.7x10^33 joules, or roughly 100x greater. As stated from the onset, Planet's stopping energy would be a minimum figure.

👆

A far better idea than simply using the "weight" of the earth under typical Earth conditions.

Originally posted by Mindship
I used a different formula, one for kinetic energy (K): K = 1/2mv^2.
- K is in joules
- m (mass) is in kilograms
- v (velocity) is in meters/second.

Let's assume this is the smallest planet possible (to get a minimum figure). This means one of its requirements to be called a planet is that it still has to be large enough to achieve "hydrostatic equilibrium." In planetary terms, this means the body has to be large enough so that its gravity is strong enough to compress it into a sphere. An astronomically well-known example is Ceres. It is the largest asteroid known (in the belt between Mars and Jupiter), and represents the minimum "planetary size": about 600 miles in diameter (the reason Ceres is not considered a planet is because it fails to meet one of the three requirements established by the International Astronomical Union: Ceres has not cleared its orbital path of debris, ie, other asteroids; but I digress).

So: the Hyperion-targeted planet (henceforth, simply called, the Planet) has a mass (like Ceres) of 9x10^20 (900 billion billion) kg. And it is moving at 500,000 mph, or (roughly) 140 miles/sec, or about 225,000 meters/sec. We now have figures we can plug into K=1/2mv^2.

K = 1/2(9x10^20) x (225,000x225,000)
K = (4.5x10^20) x (5x10^10)
K = 22.5x10^30, or 2.25x10^31 joules

By comparison, Earth's kinetic orbital energy is 2.7x10^33 joules, or roughly 100x greater. As stated from the onset, Planet's stopping energy would be a minimum figure.

By another comparison, the Sun's annual energy output per second is 3.8x10^26 joules.

According to these calculations (I strongly advise someone check my figures), this means Hyperion put out about 100,000x the power of the Sun, each second, to stop that Planet (I'm assuming it would take an amount of power equivalent to its kinetic energy).

Essentially, between what it takes to blow up a planet, and/or stop it from moving: the lesson is, rocky worlds may be small compared to a star or gas giant, but there's still a god-awful amount of matter that has to be reckoned with, far more than its mere/comparative size would suggest. This also completely ignores tidal forces, any tectonic repercussions, loss of any atmosphere, etc. It also ignores the fact that a Superman-calibre/sized being pushing against a planet would be like a BB shooting through a cake, rather than a BB pushing the whole cake.

(Also, for those interested, google "orders of magnitude joules" to see where I got some of my figures from).

Nice 👆

Originally posted by Philosophía
It's funny how you say that guy has no clue what he's talking about (and he doesn't, as he can't even make the difference between acceleration and velocity), when you're not any better.

"Stopping the planet" by itself does not imply how much energy is exerted, since that depends on the planet's velocity, so an unknown variable value being 230 smaller than a fixed value is pretty hilarious.

What are you saying here? Yes, I am operating under a lot of assumptions, I realize that. It's why I refrain from doing calcs in the first place. I was merely pointing out that his was wrong and why.

I'll give it a try for the Superman/J'onn feat.

I'm going to assume Jupiter mass, despite all evidence pointing to blatantly more (most of the ship is in the background of the Earth, skewering perspective, it hadn't yet completely showed its entire size as it was still exiting the portal, the densities of the materials for the ship have have to be ridiculously higher than Jupiter's density etc.)
The speed is 36,000 mph = 10 miles per second = 16,000 m/s
The mass if 2 * 10^27 kg.
So the kinetic energy is (m*v^2)/2 = 10^27 * 16 * 16 * 10^6

2,5 * 10^35 J
Assuming J'onn (on fire) and Superman have equal strength (yeah) that means Superman can use just 1/500 of his strength and he could stop the Earth from orbiting the sun.

But more importantly..
Even if J'onn is only 1/5 as strong as Superman, he could stop the Earth from moving around the sun with just 1/100 of his strength.

Go J'onn.

^ way off, bruh. 👇

Originally posted by Galan007
^ way off, bruh. 👇

Add some more zeros, bro. uhuh

gotta add this:

...not because i think it compares to the other ridiculousness mentioned in this thread, but because i think it's fuking badass. 👆

Originally posted by Prof. T.C McAbe
Superboy Prime changing the Center of the Universe with his bare hands. To see how impressive it is we need just to know how many years/days he needed and if Earth was the new Center, before that it was OA.

So that's mass of 100 * 2 * 10^27 = 2 * 10^29.

Now, Superboy Prime had to have moved ridiculous, incalculable amount of planets to shift the center of the Universe, so he had to have moved them fast. Let's not go into FTL, and assume 0.9c. That's 270,000,000 m/s.

So the total amount of kinetic energy Superboy Prime had to have exerted is:
1/2 * 2 * 10^29 * 27^2 * 10^14
That's:
7 * 10^45 J

In short, Superboy exerted 10,000,000,000 or 10 billion times more kinetic energy to move just one of the planets in his multi-galactical planet-moving crusade, than Superman and J'onn did in arguably the biggest strength feat in either Marvel/DC ever, with the cap at high herald.

Let that sink in.

Math.

---

Ok. Now...imagine this is PC Superboy, whose feat is so much above Prime's the zeros would look ridiculous:

Originally posted by Galan007
Whole scan:

-Superboy v1 #140.

Originally posted by Rao Kal El
Nice 👆

Mass doesn't increase with velocity.

A baseball weights the same when thrown at 5mph and when thrown at 100mph.

But comic book logic it probably does.

Originally posted by Diesldude
Mass doesn't increase with velocity.

A baseball weights the same when thrown at 5mph and when thrown at 100mph.

But comic book logic it probably does.

Mass should increase velocity if something is falling though.

Originally posted by Galan007
gotta add this:

...not because i think it compares to the other ridiculousness mentioned in this thread, but because i think it's fuking badass. 👆

Funny, I was waiting all thread for this pic (as going to mention it myself if no one else did), only where you think its badass, I personally think its utterly stupidity, and fits the title of this thread to a T. 🙂

Originally posted by Diesldude
Mass doesn't increase with velocity.

A baseball weights the same when thrown at 5mph and when thrown at 100mph.

But comic book logic it probably does.

Well it certainly does not remain a constant.

https://proofwiki.org/wiki/Einstein%27s_Mass-Velocity_Equation

Originally posted by carver9
That your calculations are right. Now calculate that Superman and Martian Manhunter showing. Then you have to include Martian Manhunter arms being abnormally large and Superman being sun amped to the equation. This should be a hard one for ya.

🙂