Which one is more impressive???

I'd like to see a reputable Hulk fan like Carver do the calcs on the Hulk feat just for shits and gigs. Seems like a pretty neato feat that outdoes almost every other Hulk feat on paper anyway.

Originally posted by h1a8
How fast was the shadow moon moving?

7,614,000 km per hour

Close to 1% of lightspeed.

Where was it said to be magic? Superman handled the constructs just fine without a scratch.

Originally posted by StiltmanFTW
[b]...

[/B]

Oooooh...

*Pops open a beer.... and two more*. I need this now..

Originally posted by CosmicComet
7,614,000 km per hour

Close to 1% of lightspeed.

Thanks!
Let’s assume the asteroid was moving at 25000m/s (the average speed of asteroids).

ENERGY
The energy to stop the shadow moon
E1 =1/2 MV^2 = 1/2 (7.35e22kg)(7.614e9m/s)^2 =2.1e42 J

The energy to stop the Asteroid
E2 = 1/2 (3 x 5.972e24kg) (25000m/s)^2 = 5.6e33 J

Therefore E1 is 380 million times greater than E2

FORCE
Let’s assume that both characters stopped the objects at the same time after impact.

The force to stop the shadow moon
F1 = M V/t = 7.35e22kg x 7.614e9m/s /t =5.6e32 /t
F2 = 3 x5.972e24kg x 25000m/s /t = 4.5e29 /t

Therefore F1 is more than 1200 times greater than F2.

Note: This assumes that the jet boots supplied no power and that all the pieces were completely stopped and not diverted.

/thread

Originally posted by Parmaniac
Stilt is from poland 😂

Is he really from Poland? You're not messing with me?

Why did I think he was from.. you know what, never mind, I already embarrassed Stilt playing the stereotype of a dumb Pollack enough in this thread (Well, half Polish, half Italian.. 🙂. )

Originally posted by abhilegend
Because the moon was completely obliterated.

Yes, fragments of the moon which can happen in any collision of such kind and even they were evaporated by the impact sometimes later.

This wasn't just "shadow" which would dissipate in the sun. Otherwise it wouldn't even exist. It was solid mass which was evaporated in the collision.

What's your point? That a small part of the shadow moon survived the collision? Or the entire moon did?

This makes alot of sense. The shadow moon wasn't alive, there was no conscience that was preventing it from fading away before superman destroyed it. So it should have just faded away on its own.
Since that didn't happen it had to be the force of the impact.

It couldn't hold its form once it got shattered.

"Force of the impact" did its job, but the fragments survived and were still around, John was watching them dissipating as he was attending to napping Kent...

That's no disintegration feat, no matter how much you wank it.

Yep. Seem desperate at this point.

Originally posted by carver9
Yep. Seem desperate at this point.

The feat doesn’t need disintegration to prove more impressive.

Let’s assume the asteroid was moving at 25000m/s (the average speed of asteroids).

ENERGY
The energy to stop the shadow moon
E1 =1/2 MV^2 = 1/2 (7.35e22kg)(7.614e9m/s)^2 =2.1e42 J

The energy to stop the Asteroid
E2 = 1/2 (3 x 5.972e24kg) (25000m/s)^2 = 5.6e33 J

Therefore E1 is 380 million times greater than E2

FORCE
Let’s assume that both characters stopped the objects at the same time after impact.

The force to stop the shadow moon
F1 = M V/t = 7.35e22kg x 7.614e9m/s /t =5.6e32 /t
F2 = 3 x5.972e24kg x 25000m/s /t = 4.5e29 /t

Therefore F1 is more than 1200 times greater than F2.

Note: This assumes that the jet boots supplied no power and that all the pieces were completely stopped and not diverted.

/thread

The numbers don't lie!

Why does h1 have wildly different numbers than that super autist in the link?

I wish the other guy was here too just to **** with H1's calculations.

Imagine a Battlezone between both.

Originally posted by Parmaniac
I wish the other guy was here too just to **** with H1's calculations.

Imagine a Battlezone between both.

Entire forum already bullied him in Movie Versus...

Originally posted by One Big Mob
Why does h1 have wildly different numbers than that super autist in the link?

Let me do the quick math myself.

1/2 x (7.342×10^22) x 2115000^2

So first you multiply the velocity by itself. I can already tell h1's calc is wrong because he seems to be have just multiplied the listed kilometers per hour by 1,000 to get the meters per hour, when the velocity in calculating kinetic energy should be in meters per second. He'd have to divide it by sixty twice afterwards.

1/2 x (7.342×10^22) x 4473225000000

Next halve the mass.

3.671e+22 x 4473225000000

Multiply the halved mass and squared meters per second velocity together:

1.6421208975e+35 = KE

So still well beyond what is required to destroy the planet Earth, which is 2.487 x 1032 J.

h1's numbers are indeed far too high, because he was using meters per hour, rather than per second.

Originally posted by CosmicComet
Could you pull that up or replicate it?

https://screwattack.roosterteeth.com/post/51230559 The user here calc'd the shadow moon feat to be 735x earth busting, a very similar figure to yours.

Ah, same number as me then. Seems that I might also be autistic.

Probably, but some of the stuff in there is too much. There's literal pixel scaling being used to find an exact distance and therefore the energy required to do said feat.

Not a rough estimate of size... pixel scaling to find the megatons.

Next level stuff.

Pixel scaling is standard for calcs across the net.

Originally posted by CosmicComet
Pixel scaling is standard for calcs across the net.

Not only that, but there's no point of reference for where the Earth went or where it needed to go in that inconsistent art where a flash of light from the heroes was country sized even though they weren't glowing. What exactly were they scaling off of?

I also found Endless Mike's Mageddon calculations too... it's a doozy. Holy shit is it ever.

It just seems too much for comics.