Originally posted by qwertyuiop1998
Interesting, the new Green Lantern Green Arrow World’s Finest Special #1 seems to be set before New Teen Titan 2. And as the comic noted, that issue is a pre-crisis story(1980)
https://ibb.co/8Y7Qh8D
👆
Also GA/GL's first run-in with Slade.
Originally posted by abhilegend
This is just the Shockwave of his punch, he is not even aiming at the planet.
It needing millions of times more energy to knock Mars out of orbit than the bench press of Earth is insane. And he's not even sun dipped. Just for fun and giggles I compared it to blowing an average planet up:
I like how for other characters it necessitates whole storyline events just to get there.....and Superman does it in some random issue, lol.
Originally posted by DarkSaint85
It needing millions of times more energy to knock Mars out of orbit than the bench press of Earth is insane. And he's not even sun dipped. Just for fun and giggles I compared it to blowing an average planet up:I like how for other characters it necessitates whole storyline events just to get there.....and Superman does it in some random issue, lol.
Obvious hyperbole aside, "Mars could fall out of orbit" isn't particularly precise. Does it mean knocking it into the Sun? Does it mean knocking it out of the Solar System? Or does it mean to deform the orbit to some degree? Because these are going to have very different values.
Also, I'd be careful with Chat GPT since it's absolutely terrible at mathematics and physics.
The kinetic energy of Mars around the Sun is 2 × 10³² J, so that's how much it would take it to stop it in its orbit and have it fall into the Sun.
To knock Mars out of the Solar System the kinetic energy you'd need is: E = mv²/2 [kinetic energy] where v² = 2GM/r [escape velocity] ⇒ E = mGM/r = 3.5 × 10³²
m = Mars' mass
G = universal gravitional contant
M = Sun's mass
r = the distance between the Sun and Mars
Any additional amount of kinetic energy added would deform Mars' orbit somewhat, so you'd have to specify what degree of deformation would be satisfactory.
Originally posted by Astner
Obvious hyperbole aside, "Mars could fall out of orbit" isn't particularly precise. Does it mean knocking it into the Sun? Does it mean knocking it out of the Solar System? Or does it mean to deform the orbit to some degree? Because these are going to have very different values.Also, I'd be careful with Chat GPT since it's absolutely terrible at mathematics and physics.
The kinetic energy of Mars around the Sun is 2 × 10³² J, so that's how much it would take it to stop it in its orbit and have it fall into the Sun.
To knock Mars out of the Solar System the kinetic energy you'd need is: E = mv²/2 [kinetic energy] where v² = 2GM/r [escape velocity] ⇒ E = mGM/r = 3.5 × 10³²
m = Mars' mass
G = universal gravitional contant
M = Sun's mass
r = the distance between the Sun and MarsAny additional amount of kinetic energy added would deform Mars' orbit somewhat, so you'd have to specify what degree of deformation would be satisfactory.
Originally posted by Astner
Obvious hyperbole aside, "Mars could fall out of orbit" isn't particularly precise. Does it mean knocking it into the Sun? Does it mean knocking it out of the Solar System? Or does it mean to deform the orbit to some degree? Because these are going to have very different values.Also, I'd be careful with Chat GPT since it's absolutely terrible at mathematics and physics.
The kinetic energy of Mars around the Sun is 2 × 10³² J, so that's how much it would take it to stop it in its orbit and have it fall into the Sun.
To knock Mars out of the Solar System the kinetic energy you'd need is: E = mv²/2 [kinetic energy] where v² = 2GM/r [escape velocity] ⇒ E = mGM/r = 3.5 × 10³²
m = Mars' mass
G = universal gravitional contant
M = Sun's mass
r = the distance between the Sun and MarsAny additional amount of kinetic energy added would deform Mars' orbit somewhat, so you'd have to specify what degree of deformation would be satisfactory.
And it would around same level energy to destroy the Earth/overcoming its GBE
And if it means to knock Mars out of the Solar System, than it would like around twice of energy to destroy the Earth
Originally posted by qwertyuiop1998
It also depending on what you mean by "destroying".
For example, the Gravitational Binding Energy of Mars is around 4.8*10^30. So destroying Mars would be like around two hundred less than having it fall into the Sun(per your calculation)And it would around same level energy to destroy the Earth/overcoming its GBE
And if it means to knock Mars out of the Solar System, than it would like around twice of energy to destroy the Earth
So yeah, it seems it is like millions of times more energy to knock Mars out of orbit than the bench press of Earth
Originally posted by abhilegend
You literally got nearly the same values lol
Originally posted by qwertyuiop1998
It also depending on what you mean by "destroying".
For example, the Gravitational Binding Energy of Mars is around 4.8*10^30. So destroying Mars would be like around two hundred less than having it fall into the Sun(per your calculation)And it would around same level energy to destroy the Earth/overcoming its GBE
And if it means to knock Mars out of the Solar System, than it would like around twice of energy to destroy the Earth
Note: Wolfram calculates the gravitational binding energy for a sphere with uniform density. Earth's density if technically not uniform, it varies with each segment and they're generally denser at the core. It's not that difficult to calculate, it's the same as the derivation of the gravitational binding energy formula but you integrate by parts. If you want a more precise value for Earth gravitational binding energy I could calculate it.
Originally posted by qwertyuiop1998
And the simplest case to lift an object is to counter gravity. So F = m g. Which means you would like 6*10^25 to lift the Earth
Generally F = GMm/r², but since on the Earth's surface M and r² are constant you can take (GM/r²) = g and so you get F = mg.
But on the surface of the moon "g" would be different.
Originally posted by qwertyuiop1998
So yeah, it seems it is like millions of times more energy to knock Mars out of orbit than the bench press of Earth
Originally posted by Astner
This time, sure. But in general it bad at coding and even worse at physics. It's better just to crunch the numbers.For Mars it would take more energy to knock it into the Sun or out of the Solar System that it would to disintegrate it, that's correct. As is knocking Mars into the Sun requiring roughly the same amount of energy as blowing up the Earth.
Note: Wolfram calculates the gravitational binding energy for a sphere with uniform density. Earth's density if technically not uniform, it varies with each segment and they're generally denser at the core. It's not that difficult to calculate, it's the same as the derivation of the gravitational binding energy formula but you integrate by parts. If you want a more precise value for Earth gravitational binding energy I could calculate it.
F = mg is is only true on the Earth's surface, on the moon it would be different.
Generally F = GMm/r², but since on the Earth's surface M and r² are constant you can take (GM/r²) = g and so you get F = mg.
But on the surface of the moon "g" would be different.
Yeah, but no one did that. What was said was: "The mountain will explode. Mars could fall out of orbit." Neither of which happened. Moreover 'Mars falling out of orbit,' is not a technical expression, and if it was intended to be then it betrays the author's unfamiliarity with orbital mechanics.
@Astner
I can't directly quote you, so I only use the quote function to address this point
Yeah, but no one did that. What was said was: "The mountain will explode. Mars could fall out of orbit." Neither of which happened. Moreover 'Mars falling out of orbit,' is not a technical expression, and if it was intended to be then it betrays the author's unfamiliarity with orbital mechanics.
Originally posted by DarkSaint85
It needing millions of times more energy to knock Mars out of orbit than the bench press of Earth is insane.
Originally posted by qwertyuiop1998
@Astner
I can't directly quote you,
Originally posted by qwertyuiop1998
I was actually referring to DS' post.