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CEO, BS Comics
Originally posted by nvrbeenwthagirl
If you were to pull the earth in free floating space, all you'd have to do is calculate the mass of the earth. But your not. Your pulling the Earth's mass against the orbit in which it holds. YOur pulling the mass of the earth (one amount of force needed) against the Sun's pull/Earth's Orbit ( another amount of force needed)( One amount of force needed)*(Another amount of force needed)=the True mass or force needed. Kthanks Bye.
You haven't brought in going against the orbital velocity until now and it certainly wasn't factored into that last equation - in any event in the tangential plane the Earth moves at a constant velocity i.e. forces are balanced.
The central force acting as the centripetal force for the Earth's orbit is the gravitational attraction between the Earth and the Sun...
Originally posted by nvrbeenwthagirl
well first of all, I went to find out how much the sun's gravitational pull would effect the earth's orbit.
I.e. this statement is silly, the "gravitational pull" is the essentially the entirety of the force holding the earth in orbit in the plane perpendicular to the tangent. If the Sun wasn't there the Earth would hurtle through space in a straight line forever.
Originally posted by nvrbeenwthagirl
I then found out how big the sun was in relation to the earth. to get a relative comparison on weight. Thing is, in space, there is no weight persay, but there is mass.
A mass ratio really has no bearing on the gravitational force between two bodies, though the actual masses do.
Originally posted by nvrbeenwthagirl
So I took the mass of the earth, times the gravitation pull of the sun, and times the sun's own size against that of the earth to come up with what it would be like to move the earth against the sun's pull.Now to destroy a planet, scientist have already done this one for me. Google. they've also said how much force it would take to Knock earth out of orbit. Google. It's your best freind.
You know if I use your equation to calculate the gravitational attraction between two suns I get the sun's mass times the gravitational attraction between the suns... with units kg^2 m per s^2... which makes no sense.
Alternatively since your equation seems to be constantly changing if I do what you did above and for some reason multiply two forces to somehow derive a "force." I get units of kg^2 m^2 per s^4... which makes even less sense.
The SI units of force are Newtons. They break down to kg m per s^2
The gravitational force between the Earth and the Sun can be calculated by Newton's Universal Law of Gravitation.
Funnily enough it has units of kg m per s^2.
KTHXBI