Originally posted by abhilegend
You want power scaling? Here Five Supergirls were needed to pull just Superman out of source wall and make a small fracture in source wall.http://www.turboimagehost.com/p/16076089/Superman_Batman_25-01.JPG.html
http://www.turboimagehost.com/p/16076090/Superman_Batman_25-0203.JPG.html
Superman alone destroyed a planet size chunk out of source wall.
http://s1113.photobucket.com/albums/k508/abhilegend/Superman/?action=view¤t=Superman-Batman0422008MinuteMen-DarthScanner017.jpg
http://s1113.photobucket.com/albums/k508/abhilegend/Superman/?action=view¤t=Superman-Batman0422008MinuteMen-DarthScanner018.jpg
http://s1113.photobucket.com/albums/k508/abhilegend/Superman/?action=view¤t=Superman-Batman0422008MinuteMen-DarthScanner021.jpg
http://s1113.photobucket.com/albums/k508/abhilegend/Superman/?action=view¤t=Superman-Batman0422008MinuteMen-DarthScanner022.jpg
That was after overpowering the pull of Source Wall itself.
That's how you destroy a planet. Not by a puny hammer.
👆
yup yup, also heres the 700 plus earth punch feat!
1) Now first of all, I'd like to clear up some shit on this page specifically in regards to where the Moon's mass is stated on-panel:
"The Shadow's mass will be the same as the real Moon."
"81 Billion tons."
Now, that second line of dialogue, as stated by Batman, is false - the Mass of the Moon is not 81 Billion tons but is instead, in fact, much closer to 81 Billion Billion tons at 81 Quintillion tons, or at 73 Sextillion kilograms. I've also heard marvel **** drip try and suggest that the DC Comics variant of the Earth's Moon had possessed one billion times less mass than our real-life Moon, but this claim is also false. The writer of Justice League Vol. 2 #30, Dwayne McDuffie, had later specifically mentioned on his own website that he had tried to, and made a error in, calculating the real-life Moon's mass for this comic, as well as that he had originally intended to utilize the actual Moon's mass of 81 Quintillion tons. This is also very evident even in the dialogue itself, where it's clearly stated that the Shadow Moon's mass "will be the same as the real Moon", yet the distinction still wouldn't make much sense, if Earth's Moon in the DC Universe had possessed one billion times less mass than our real-life Moon.
2) For some "reason", some people always seem to selectively forget the basic scientific principal of "Force = Mass*Acceleration", even when it's been spoon-fed to them - it's also even funnier because that exact same comic, which had mentioned the F=MA equation on-panel, has already established that the Mass of the Shadow Moon, as well as the fact that it was heading to Earth. Still, do we know just how fast it was going?
"My ring clocks it at 7,614,000 km per hour"
...and thank you, Green Lantern! Now, we have everything that we need to figure out just how much Kinetic Energy the Shadow Moon was exerting while heading for Earth, and how much Superman had to exert to stop it! Keep in mind that Superman didn't simply "stop" the Shadow Moon either - he actually was able to not only match the Shadow Moon's forward momentum, moving at 7,614,000 km per hour or 2,115,000 m/s, but also outright shattered it into fragments and exerted far more than the necessary power to pulverize it.
KE = 1/2mv^2
KE = 1/2(73 Sextillion*2,115,000)^2
KE = 1.632727124e+35 Joules
Calculating the Kinetic Energy of the Shadow Moon has given us a result of 3.9 Quintillion Megatons of force - that's enough energy to destroy Earth 735.84x over!!!! good god... ****ing supes!!!!! heres the feat in action:
SUPERMAN punches with the force to shatter over 700 earths. **** a gladiator
