Batman vs Gamora...

Originally posted by h1a8
I didn't err. I stated the entire skeleton to get a basis for a laced skeleton. Please reread my post. You would see that I actually claim a laced skeleton.

If Logan's skeleton is entirely adamantium (it's not) then the density of adamantium can be calculated to approximately 4kg/m^3. Steel is over 8kg/m^3. So a 2lb katana sword would weigh 1lb in adamantium.

Now since Logan's skeleton is not entirely adamantium but rather a fraction of it. Reducing the volume and keeping the weight increases the density.
So if 1/6 of Logan's skeleton is adamantium while retaining the weight (100lb) then we can increase the density 6 more times and thus the weight of an adamantium sword from 1lb to 6lb. This is just a rough estimate. For example if adamantium is 1/8 of his skeleton then the sword would weight 8lb.

Yeah, you assumptions are way off, however, in estimating how much adamantium there is. The covering is only a very thin coating; as a guide, composite coatings on bone scaffolds for joint replacements is 2 micrometres thick, or 2^-6 metres. Source: https://www.oapublishinglondon.com/article/1170

What is the surface area of someone's bones? 500m^2, roughly (based on: http://www.envarch.net/publications/circaea/9.2/9-2-antoine.pdf)

So, the volume of adamantium required to coat the bones of an average man (which is being generous, as we all know Wolverine is nowhere near the height of an average man) is 0.0015m^3, assuming I extracted it all into a flat sheet.

This 0.0015m^3 of adamantium weighed 48.1kg (source:http://marvel.wikia.com/Wolverine_%28James_%22Logan%22_Howlett%29yes, I know, a handbook and a wiki).

Therefore, the density of adamantium is 32066kg/m^3.

Originally posted by DarkSaint85
Yeah, you assumptions are way off, however, in estimating how much adamantium there is. The covering is only a very thin coating; as a guide, composite coatings on bone scaffolds for joint replacements is 2 micrometres thick, or 2^-6 metres. Source: https://www.oapublishinglondon.com/article/1170

What is the surface area of someone's bones? 500m^2, roughly (based on: http://www.envarch.net/publications/circaea/9.2/9-2-antoine.pdf)

So, the volume of adamantium required to coat the bones of an average man (which is being generous, as we all know Wolverine is nowhere near the height of an average man) is 0.0015m^3, assuming I extracted it all into a flat sheet.

This 0.0015m^3 of adamantium weighed 48.1kg (source:http://marvel.wikia.com/Wolverine_%28James_%22Logan%22_Howlett%29yes, I know, a handbook and a wiki).

Therefore, the density of adamantium is 32066kg/m^3.

Better be careful man, you're going to give people brain turds.

Lol. Was just a bit of fun, nothing serious. But it just is to show that adamantium katanas will be heavier, and thus, will throw Batman off. Would it throw him off enough to make a difference? No, because the result never changed.

Gamora wins.

Originally posted by DarkSaint85
Lol. Was just a bit of fun, nothing serious. But it just is to show that adamantium katanas will be heavier, and thus, will throw Batman off. Would it throw him off enough to make a difference? No, because the result never changed.

Batman wins.

👆

Originally posted by DarkSaint85
Lol. Was just a bit of fun, nothing serious. But it just is to show that adamantium katanas will be heavier, and thus, will throw Batman off. Would it throw him off enough to make a difference? No, because the result never changed.

Gamora wins.

Very true.

Originally posted by Silent Master
Batman wins.

Agreed!

🙂

Well, h1a8 was going to post 3 speed feats that DCnU Batman has, whilst weighted down, which sh!t on the feat I posted. I haven't seen it. Nor has anyone else.

So Gamora has the better feats, so far.

Originally posted by DarkSaint85
Lol. Was just a bit of fun, nothing serious. But it just is to show that adamantium katanas will be heavier, and thus, will throw Batman off. Would it throw him off enough to make a difference? No, because the result never changed.

Gamora wins.

Originally posted by Silent Master
Very true.

Originally posted by TheLordofMurder
Agreed!

🙂

Originally posted by DarkSaint85
Lol. Was just a bit of fun, nothing serious. But it just is to show that adamantium katanas will be heavier, and thus, will throw Batman off. Would it throw him off enough to make a difference? No, because the result never changed.

Gamora wins.

So true. It really doesn't take a mental giant to realize that she'd take those heavy swords away from him, and spank him with them. Swords of that weight would likely make him drop one and hold the other with both hands. Guess what that means? 😂

Batman stomps 10/10

Originally posted by Board Walker
Batman stomps 10/10

Originally posted by quanchi112
Based on ?

He's Board Walker.

Originally posted by quanchi112
Based on ?

Truth

Originally posted by KingD19
He's Board Walker.

Basically.

Originally posted by Silent Master
You don't listen very well, do you? his skeleton doesn't weigh 100 pounds because of the adamantium....he has over 100 pounds of adamantium bonded to his skeleton.

IOW, it's weight of his skeleton + 100 pounds of adamantium. and not skeleton + weight of admantium = 100 pounds.

LOL, the biggest mistake is to underestimate me. I already knew this and thus it was part of my initial calculations.
I did a rough calculation (quick over estimate). But wasn't very efficient in the strategy.

I'll be more precise in the explanation.
Here is the calculation:
Let's first assume Logan's skeleton is 100% adamantium (It is not).
So adamantium skeleton weighs about 105lbs (47.63 kg)
An average skeleton's volume is about .015m^3.
So the density of adamantium is 47.63/.015 kg/m^3 = 3175kg/m^3
The density of steel is about 8000kg/m^3 and a katana sword weighs no more than 4lb. So the weight of an adamantium katana sword would weigh
3175/8000 x 4lb = 1.59lb.

Now since Logan's skeleton is only a fraction adamantium (in volume). Let's say that 1/8 of his skeleton is bonded to adamantium. That would mean the density and thus weight of the adamantium katana is now 8 x the previous estimate. So the weight of an adamantium katana sword is now 8 x 1.59lb = 12.7lb.

I could have done this calculation a little simpler and used a more efficient and more straightforward strategy to prevent confusion. Here is the more efficient calculation.
Assume the ratio of volume of adamantium to total volume of Logan's skeleton is 1/8. Also assume the volume of Logan's skeleton is 0.015m^3. Therefore the density of adamantium = 47.63kg/(1/8 x .015m^3) = 25402kg/m^3.

Since the density of steel is 8000kg/m^3 and the weight of a katana sword is at most 4lb then the weight of an adamantium katana sword would be 25402/8000 x 4lb = 12.7lb.

Originally posted by h1a8
LOL, the biggest mistake is to underestimate me. I already knew this and thus it was part of my initial calculations.
I did a rough calculation (quick over estimate). But wasn't very efficient in the strategy.

I'll be more precise in the explanation.
Here is the calculation:
Let's first assume Logan's skeleton is 100% adamantium (It is not).
So adamantium skeleton weighs about 105lbs (47.63 kg)
An average skeleton's volume is about .015m^3.
So the density of adamantium is 47.63/.015 kg/m^3 = 3175kg/m^3
The density of steel is about 8000kg/m^3 and a katana sword weighs no more than 4lb. So the weight of an adamantium katana sword would weigh
3175/8000 x 4lb = 1.59lb.

Now since Logan's skeleton is only a fraction adamantium (in volume). Let's say that 1/8 of his skeleton is bonded to adamantium. That would mean the density and thus weight of the adamantium katana is now 8 x the previous estimate. So the weight of an adamantium katana sword is now 8 x 1.59lb = 12.7lb.

I could have done this calculation a little simpler and used a more efficient and more straightforward strategy to prevent confusion. Here is the more efficient calculation.
Assume the ratio of volume of adamantium to total volume of Logan's skeleton is 1/8. Also assume the volume of Logan's skeleton is 0.015m^3. Therefore the density of adamantium = 47.63kg/(1/8 x .015m^3) = 25402kg/m^3.

Since the density of steel is 8000kg/m^3 and the weight of a katana sword is at most 4lb then the weight of an adamantium katana sword would be 25402/8000 x 4lb = 12.7lb.

I'd say it's more like 16lbs, or 7.3kg if you wanna get nasty.

Originally posted by DarkSaint85
Yeah, you assumptions are way off, however, in estimating how much adamantium there is. The covering is only a very thin coating; as a guide, composite coatings on bone scaffolds for joint replacements is 2 micrometres thick, or 2^-6 metres. Source: https://www.oapublishinglondon.com/article/1170

What is the surface area of someone's bones? 500m^2, roughly (based on: http://www.envarch.net/publications/circaea/9.2/9-2-antoine.pdf)

So, the volume of adamantium required to coat the bones of an average man (which is being generous, as we all know Wolverine is nowhere near the height of an average man) is 0.0015m^3, assuming I extracted it all into a flat sheet.

This 0.0015m^3 of adamantium weighed 48.1kg (source:http://marvel.wikia.com/Wolverine_%28James_%22Logan%22_Howlett%29yes, I know, a handbook and a wiki).

Therefore, the density of adamantium is 32066kg/m^3.

Adamantium is bonded to his skeleton. It is MIXED IN creating adamantium beta. You are assuming covered only. 1/8 should be a better estimate.

Anyway, using your density estimate shows that an adamantium katana (which weighs about 2-3lb in steel) weighs about 8-12lb which is close to my initial estimates.

P.S. Logan may not be as tall as an average human (5'7"😉 but he is more stocky and wider (his bone volume should be larger).

Originally posted by DarkSaint85
I'd say it's more like 16lbs, or 7.3kg if you wanna get nasty.

In that calculation, I used the heaviest type of katana sword, which weighs 4lb. Most katana swords are around 2-3lb. So let's say 8-12lb ok?

Originally posted by h1a8
Adamantium is bonded to his skeleton. It is MIXED IN creating adamantium beta. You are assuming covered only. 1/8 should be a better estimate.

Anyway, using your density estimate shows that an adamantium katana (which weighs about 2-3lb in steel) weighs about 8-12lb which is close to my initial estimates.

Well, no.

Paint is bonded to a surface. I'm not going to say that my paint coat is mixed into the table I've just painted, am I?

In any case, semantics. We both arrived at roughly the same amounts. Although I do like how you changed from using a max to now using 2-3lbs, just so your initial estimates (whcih would've been out by a fair bit) can be closer.

Originally posted by h1a8
In that calculation, I used the heaviest type of katana sword, which weighs 4lb. Most katana swords are around 2-3lb. So let's say 8-12lb ok?

I say......10lb, just to get the median. 😠

So. Two 10lb weights attached to his hand. Starting distance, 0.5km, line of sight, no obstacles in the way.

I'm gonna need to see some fighting speed feats of Bats whilst weighted down, which would be faster than Gamora's.