For some reason, the link above is broken. Reposting.
https://www.quora.com/In-which-region-of-an-H-R-diagram-do-neutron-stars-fall
If still having trouble with this one, copy/past below:
"https://www.quora.com/In-which-region-of-an-H-R-diagram-do-neutron-stars-fall"
Originally posted by Nibedicus
Just to shut h1 up, I did a quick google on typical luminosities of neutron stars. As calculated by:Jonathan Devor, PhD Astronomy, Harvard University (2008)
And I quote:
To figure out the luminosity of such neuron stars we’ll assume they all have a radius of R= 10 km, and that they behave like black bodies. If so, we can apply the Stefan–Boltzmann law:
L=4πσR2T4≈(T1K)4⋅71.3W≈(T106K)4⋅0.186Lsolar
So a typically neutron stars will have a luminosity of about 0.186 times solar luminosity, though very young neutron stars can have a luminosity that is much much higher than that.
Source: https://www.quora.com/In-which-regi...tron-stars-fall
Note: the cut/paste of the computation doesn't translate well from the post. Just click on the source to look at it.
So the Because Science guy was slightly off but pretty close. It is not 1/4 but around a little under 1/5th.
IOW, h1 sucks at math and science
It's also a good thing Sience guy was being so conservative, since he could have considered that blast of energy to be a soft gamma-ray repeater bursts which can have a luminosity of more than 10^45 ergs per second.
Originally posted by Nibedicus
Also, dialogue between Thor and Eitri.Eitri: With the iris closed, I can't heat the metal.
Thor: How long will it take to heat it?
Eitri: A few minutes, maybe more. Why?
Thor: I'm gonna hold it open.While time stamps put it at 55 seconds, writer's intent is clear as Eitri mentions that it takes more than a few minutes to heat up the metal. And time skips most likely have occurred between cuts cuz ppl sitting and waiting for 3 minutes while the metal heats wouldn't be the most dramatic. Means at least 3+ minutes. NOT below 1 minute, so lol on the attempted lowballing there.
I disagree that time skips. Everything is shown in real time. There is no indication of a time skip.
But even assuming 3 minutes. Then it's still all about power (or temperature).
My hand can get hit with 100,000J of heat energy in over 3 minutes from a space heater. It's not a feat. Total energy is not a feat. It's the power or temperature that matters.
Thor got hit with a 600,000k to 100,000k beam.
In other words, Thor can withstand temperatures (without dying) of 600,000k for a certain amount of time.
Originally posted by Nibedicus
For some reason, the link above is broken. Reposting.https://www.quora.com/In-which-region-of-an-H-R-diagram-do-neutron-stars-fall
If still having trouble with this one, copy/past below:
"https://www.quora.com/In-which-region-of-an-H-R-diagram-do-neutron-stars-fall"
Neutron stars fluctuate in surface temperature depending on various factors (such as age). When quantifying feats its always best to use lower estimates so that no one will have a problem with the numbers.
That's why I used 600,000k as the temperature (from the source I posted).
The dialogue was so blatantly explicit for the Thor feat, it was as if I wrote it to shut up people like H1, myselF. Shockingly, it's still not enough. Maybe we can have little power meters indicating what the feats are accomplishing when explicit dialogue and visual confirmation aren't enough. Lol.
The full force of a Star. Explicitly stated. Just the heat. GG.
Originally posted by h1a8
Neutron stars fluctuate in surface temperature depending on various factors (such as age). When quantifying feats its always best to use lower estimates so that no one will have a problem with the numbers.
That's why I used 600,000k as the temperature (from the source I posted).
Nice try at attempting to lowball. Nice try attempting to appear competent when you don't know wtf you're doing. Funny thing was, if I didn't blow your little sham out of the water, you'd have tried to pass it off as right by default (w/c is what you always do). This is why people don't take you seriously.
Took me 10 minutes of google. Maybe learn to use that before spouting BS math?
Nice try at attempting to dodge my BZ challenge. You know I'll wreck you so bad, you'll never want to show your face here again.
Originally posted by h1a8
I disagree that time skips. Everything is shown in real time. There is no indication of a time skip.But even assuming 3 minutes. Then it's still all about power (or temperature).
My hand can get hit with 100,000J of heat energy in over 3 minutes from a space heater. It's not a feat. Total energy is not a feat. It's the power or temperature that matters.
Thor got hit with a 600,000k to 100,000k beam.
In other words, Thor can withstand temperatures (without dying) of 600,000k for a certain amount of time.
You don't know jack about physics so maybe you should shut up and stop making these BS theories? No one believes you, y'know.
Again, reverting back to: https://youtu.be/bOLOBJSJL0I
That you never debunked. No matter how much fake math or physics you threw around.
Also, you are such a dishonest lying little troll:
Originally posted by h1a8
You can't use real time (our time) here. All of the scenes are not necessarily connected (without gaps) in time. Meaning, time has elapsed between some adjacent scenes.
http://www.killermovies.com/forums/newreply.php?s=&action=newreply&postid=16544106
Apparently time skips between scenes only happen when h1 wants them to.
And I notice you're still trying to distract from my BZ challenge. Maybe you think I'll forget?
Originally posted by Rage.Of.Olympus
The dialogue was so blatantly explicit for the Thor feat, it was as if I wrote it to shut up people like H1, myselF. Shockingly, it's still not enough. Maybe we can have little power meters indicating what the feats are accomplishing when explicit dialogue and visual confirmation aren't enough. Lol.The full force of a Star. Explicitly stated. Just the heat. GG.
Everyone in their right mind believes it was the heat of the star that Thor experienced. You are the only one that thinks otherwise.
Even the phucking science guy thinks it was heat. He keep saying "heat energy".
Originally posted by Nibedicus
You don't know jack about physics so maybe you should shut up and stop making these BS theories? No one believes you, y'know.Again, reverting back to: https://youtu.be/bOLOBJSJL0I
That you never debunked. No matter how much fake math or physics you threw around.
Also, you are such a dishonest lying little troll:
http://www.killermovies.com/forums/newreply.php?s=&action=newreply&postid=16544106
Apparently time skips between scenes only happen when h1 wants them to.
And I notice you're still trying to distract from my BZ challenge. Maybe you think I'll forget?
You are lazy.
If you would plug the numbers in yourself and you will see that my numbers are correct. Stop taking people word for it and do it yourself.
This is not calculus you know. Simple equations. Plug and chug.
Originally posted by h1a8
He made several errors
1. He claims a neutron star is 1/4 as luminous as the Sun (he writes this on the screen with 0.25Lo) then says that means that a neutron star emits 1/4 the power that the sun does.
But this contradicts the equation
Power = 4pi*r^2*sigma*T^4.
Plugging in r=10^4m and T=600,000k (not 10^6 k) for neutron star in the power equation and
R=6.957x10^8m and T=5778k for Sun in the power equation gives
The power of a neutron star is 0.024 times that (not 1/4 of) of the Sun.2. The ratio of the amount of power that Thor was getting hit with and the total power output of a neutron star should be the same ratio as the cross sectional area of Thor and the total surface area of a neutron star. This ratio is
R=1.4/[4pi(10^4)^2]= 1.11e-9 (assuming Thor is 2m x 0.7m rectangle)So Thor experienced 0.024 x 1.11e-9 = 2.67e-11 times the power of the Sun.
Thor had it opened for less than 60s (from the timestamp).
So Thor tanked less than 2.67e-11 x 3.828e26 x 60s = 6.14e17 J of heat energy.
Very impressive.This is making some assumptions though as one source states that some neutron stars have millions of times less luminosity than that of the Sun and can reach surface temperatures of about 50,000k.
Originally posted by Lestov16
Supes can withstand it. The question is would he be launched if he braced for impact.
Yes, he'll be launched. Nothing we've seen from Superman indicates he can completely tank a hit from someone like Hulk without budging. I don't think it will KO him, but he's not just shrugging it off like Diana's headbutt.
Originally posted by h1a8
You are lazy.
If you would plug the numbers in yourself and you will see that my numbers are correct. Stop taking people word for it and do it yourself.
This is not calculus you know. Simple equations. Plug and chug.
Lol. You just had 2 actually credentialed individuals point out that the conclusion of your "science" is wrong. Meaning that the very premise of it is flawed. It doesn't matter if your math "adds up", you moron. Why would I need to waste my time checking it?
And stop being such a coward. Accept my BZ already or GTFO here.
Originally posted by Nibedicus
Lol. You just had 2 actually credentialed individuals point out that the conclusion of your "science" is wrong. Meaning that the very premise of it is flawed. It doesn't matter if your math "adds up", you moron. Why would I need to waste my time checking it?And stop being such a coward. Accept my BZ already or GTFO here.
How so? What two individuals did this?
Sigma is a constant.
I used the same formula (the same one science guy used, the same one you posted).
We know the radius of a neutron star (10km)
We know that 600,000k is a possible surface temperature
We know the Sun's surface temperature and radius.
Plugging in these values into the power equation and then dividing the two results gives us the ratio of power from a neutron star to the Sun.
Plug the numbers into the formula yourself and you will see.