Can JL Superman Tank Hulks Leviathan Punch?

Started by Silent Master31 pages
Originally posted by h1a8
It sliced an i beam in half with a swipe.
It takes a LARGE amount of heat energy to melt steel that fast.

Remember when you tried to claim it took star level energy to cut an I-beam?

Nibedicus, do you think you could do me a solid and repost what you posted last, and hopefully I can quote it this time?

……

Yeah, quote (and edit) functions are broken for some reason. Reposting. 🙂

While we agree that the purpose of the Motherbox is to terraform worlds, you seem to be missing a few important pieces in your logic:

Superman was exposed to energies of a single motherbox for a very short period of time.

This is important because of a few reasons:

1) The motherboxes themselves (individually) DO NOT possess the power to reshape a planet. They need to combine to form the Unity. Where, as Cyborg explained:

Cyborg: The Unity brings all three boxes together in perfect sync. Its power builds until it can't be contained. But if I can cause a delay between each box, even for a nanosecond… Its energy will cascade. Form a loop. And they'll feed on each other.
Flash: And that's it? We just pull them apart? No fuss, no muss?
Cyborg: Separating the boxes is still gonna cause a massive surge.

This is very important because we do not know exactly (by quantification) how the relationship between the 3 Motherboxes generate the types of energy needed to perform the the planet-reshaping. We have an idea how it is being done, but not the numbers behind it. It could be an additive relationship (1/3 of 3), but it can also be multiplicative or even exponential (ex. the power gem, by itself is planetary, combined with the other gems+the gauntlet then it is universal in scope). And I am more inclined to believe in it being multiplicative/exponential in nature (due to the fact that Unity is even necessary, also see below).

2) The aspect of time. We do not know how long it takes for the Unity to reshape the surface of the planet (as we see it do during the WW flashback as well as end battle of the movie). But from what is shown, it seems to take quite a bit of time to do.

Here is a scene where they were talking about the Unity Earth change hitting a nearby resettlement:

Cyborg: The Earth starts changing, it’ll hit them first.
Batman: How long have we got?
Cyborg: A few hours.

A few hours to hit a nearby settlement (a few square miles?). That is not an instant-power release but a slow building-up process. In fact it may take many many many years (even if 10 sq miles = 1 hour it would take the device 2000 years to cover the almost 200 million square miles of the Earth's surface), than it would take to encompass the planet unless the buildup was exponential in nature (w/c is another reason why I think the relationship between boxes is exponential).

Superman was energized by a single Motherbox for a few seconds (about ten seconds). Less time than it took (about 15 seconds as seen when Steppenwolf combined it before the end battle) for 3 fully awake Motherboxes to even combine to even trigger Unity.

From the aspect of time and the fact that this was done using single motherbox, I strongly disagree on the planetary-surface (or even close to it) scale of the "feat".

It's funny because I can't quote this post either. 👆

Oh well, I'll do it manually some other time.

Originally posted by NemeBro
It's funny because I can't quote this post either. 👆

Oh well, I'll do it manually some other time.

You should be able to quickquote it...

Quickquote doesn't let me break up the post though.

Originally posted by NemeBro
Quickquote doesn't let me break up the post though.

quickquote and write. Then Edit your post and you should be able to break 😉

Originally posted by Silent Master
Remember when you tried to claim it took star level energy to cut an I-beam?

The heat energy in a beam that swipes and cuts an I beam in half has to have at least the temperature of a star.

Originally posted by h1a8
The heat energy in a beam that swipes and cuts an I beam in half has to have at least the temperature of a star.

"At least the temperature of a star" is meaningless. Quantify.

Certain stars (a brown dwarf) have the temp of freshly brewed coffee.

https://news.nationalgeographic.com/news/2011/03/110323-coldest-star-discovered-cup-coffee-brown-dwarf-hawaii-space-science/

And still waiting on the BZ acceptance. Or have you conceded that your math is just as brown as that dwarf?

Poop analogies! 😱

Originally posted by juggerman
Poop analogies! 😱

IKR?

😱

Originally posted by h1a8
The heat energy in a beam that swipes and cuts an I beam in half has to have at least the temperature of a star.

If the full power of a neutron star is 100, what is cutting an I-beam?

Originally posted by Silent Master
If the full power of a neutron star is 100, what is cutting an I-beam?

Let’s not change terms now.
We are talking about heat energy.

If the temperature of the beam Thor got hit with is 100 then the hv could range from 50 to 70. It usually take many seconds to melt steel.

Originally posted by Nibedicus
"At least the temperature of a star" is meaningless. Quantify.

Certain stars (a brown dwarf) have the temp of freshly brewed coffee.

https://news.nationalgeographic.com/news/2011/03/110323-coldest-star-discovered-cup-coffee-brown-dwarf-hawaii-space-science/

And still waiting on the BZ acceptance. Or have you conceded that your math is just as brown as that dwarf?

Brown dwarfs are not stars.

Originally posted by h1a8
Brown dwarfs are not stars.

Science >>>>>>> h1

https://en.wikipedia.org/wiki/Brown_dwarf

H1 humiliating himself once again.

Originally posted by h1a8
Let’s not change terms now.
We are talking about heat energy.

If the temperature of the beam Thor got hit with is 100 then the hv could range from 50 to 70. It usually take many seconds to melt steel.

LOL at h1 thinking it takes 50 to 70% of 2x10^20 to melt steel.

Originally posted by Silent Master
Science >>>>>>> h1

https://en.wikipedia.org/wiki/Brown_dwarf

Edit: from the link

Further gravitational contraction is prevented and the result is a "failed star", or brown dwarf that simply cools off by radiating away its internal thermal energy
Originally posted by Silent Master
LOL at h1 thinking it takes 50 to 70% of 2x10^20 to melt steel.

1) Thor didn't experience 2x10^20J of heat energy
2) My statement was about speed (how fast to melt steel)

2) shows either you are an idiot or you are a troll