Endless Mike
Sqirrel Girl fanboy
Originally posted by h1a8
I meant gas in liquid form, like the gas we use to fill our cars.
Oh, okay. But still, solid fuel is also common.
You can drive something somewhere else by diverting it. Common sense.
Reed stated, "You have to make it SERVE off course." That proves writer's intent.
That's the minimum he had to do, but it was then stated that he drove it there, which I imply to mean using his own strength. But I can see how your interpretation is also valid.
I never heard of a spaceship being anchored.
Anchor it to a planet, space station, moon, wherever it's docked at. Seems simple enough to me.
https://www.dictionary.com/browse/anchor
noun
1. any of various devices dropped by a chain, cable, or rope to the bottom of a body of water for preventing or restricting the motion of a vessel or other floating object, typically having broad, hooklike arms that bury themselves in the bottom to provide a firm hold.
2. any similar device for holding fast or checking motion: an anchor of stones.
verb (used with object)
3. to hold fast by an anchor.
4. to fix or fasten; affix firmly: The button was anchored to the cloth with heavy thread.
verb (used without object)
5. to drop anchor; lie or ride at anchor: The ship anchored at dawn.
6. to keep hold or be firmly fixed: The insect anchored fast to its prey.
Definitions 3, 4, and 6 seem to fit just fine.
You don't understand a two fold argument do you? The 2nd part of my argument assumed it was a spaceship. Why focus on the 1st part (whether it's a boat or spaceship)? That's irrelevant. You suppose to defeat the 2nd part first (the most important) then defeat the 1st part if I concede the 2nd part.
Well I was just responding to everything you said. I argued both for it being a spaceship and for restraining something that could anchor a spaceship being a strength feat. I don't see why it really matters so much what order I put my arguments in.
I didn't argue that there was NO propulsion. I argued that fictional spaceships are known to use antigravity (to become weightless) so that they can escape to space with minimal use of fuel. They also can warp space in order to achieve FTL travel (or travel in hyperspace). Those factors make the propulsion strength unknown.
Except for:
A. We clearly see exhaust coming from the Skrull Battlecruiser (the specific type of spaceship referenced here) as it's flying through space. That means it's using a reaction drive (a drive that propels a vessel by releasing exhaust in the opposite direction of its movement).
B. Even if a spaceship used antigravity to make itself weightless, that wouldn't do anything to help it escape a physical block that was anchoring it to the ground.
C. The Skrull made a point of being impressed by Ben's feat. He clearly treated the block as something very strong, due to its ability to 'anchor a battlecruiser', and found it unbelievable that Ben was able to break it. That indicates that it would require a lot of force to do so. It only makes sense to say it's comparable to the force of the ship's engines moving it.
You can't compare a fictional spaceship (with unknown size and composition) to anything. In all honesty, that ship looks small. The front dome appears to have a diameter of 10-12ft (using the size of Nova). The ship can weigh anything from 200-1000 tons for all we know.
I could measure it, but I'm too lazy lol. Anyway, it would still be higher than its base mass/weight due to the thrust of its engines.
Lastly, the weight of a ship has absolutely nothing to do amount of EXTRA WEIGHT it can pull (External load). For example, a ship can weigh 100 tons but have a maximum external load limit of 10 tons. Less than 100 tons is used to anchor real battle cruisers (which weigh tens of thousands of tons).
We're talking about a spaceship, though. It's not the same as a water anchor, it would have to hold the ship to a planet against the power of the ship's engines, which has to be sufficient to achieve escape velocity.
Energy and force are 2 different things.
Minimum Energy used (or work done) = Force x Displacement.
So divide that energy number by the diameter of a planet. You would get a small amount of force (less than 1000 tons).A bullet can quickly penetrate a particular distance of a planet with a small amount of force (we feel the force as recoil).
Please show your math for this to prove it's less than 1000 tons. I did a calc and got over 8 megatons of energy.
I already calced the surface area of the press, but this time I will use compressive strength. Again, assuming an earthlike planet, average crust depth = 45 km. Double that for both sides of the planet. CS of rock = 200 Mpa.Volume of the tunnel through the crust = 38,464.8183 m^3.
38,464.8183 * 200 * 1,000,000 = 7.69296366e12 j.
The mantle is composed of several layers, the Mohorovicic discontinuity is basically rock and extends to around 200 km deep, so I can use 200 MPa for that. Subtracting the crust and multiplying for both sides of the planet, we get a volume of 132,489.9297 m^3.
132,489.9297 * 200 * 1,000,000 = 2.649798594e13 j.
I found a paper with a graph of CS of rock (magma) under pressure:
https://books.google.com/books?id=3DUrAAAAYAAJ&pg=PA247&lpg=PA247&dq=compressive+strength+of+magma&source=bl&ots=4cegKuia8-&sig=Ni5i7pz30t8pISXiZzTD3f3zyHM&hl=en&sa=X&ei=3AZQUYexJpen4AOnwoDQAw#v=onepage&q&f=false
The only pressure I could find for the mantle was 140 GPa at the bottom of it, for an average I'll use half of that. Unfortunately, no equation is given with the chart, so I'll have to construct one. To go low-end (and since a large part of the mantle is made of it), I'll use peridotite. Its CS under a pressure of 2 kilobars is about 8 kilobars. Its CS under 1 is about 5. It seems to grow steadily after the initial upswing. This indicates a CS increase of 3 kilobars per kilobar of pressure. 70 GPa = 700 kilobars, or about 2102 kilobars CS. That's 210,200 Mpa. However, as we will see later, this is way too high. The graph must level off at some point. Just as an estimate, based on the values I got for the core, I'll divide this by 100.
Since we'll be using 2440 km for the inner core's diameter, and 2266 * 2 km for the outer core, add these and the crust and Moho we already did, then subtract them from the Earth's diameter to get 5370 km for the mantle. Volume of the tunnel through the mantle = 2,295,067.492 m^3.
2,295,067.492 * 2102 * 1,000,000 = 4.824231868e15 j.
I found an equation for the CS of iron under pressure (the inner and outer cores are nickel-iron, but I couldn't find that, so this is the best I could do).
Pressure of the outer core ranges from 140 to 330 GPa. Using the average.
CS = 2.9 + 0.028 * 235 = 9.48 Gpa
Width of outer core = 2266 km, double that for both sides of the planet. Volume of the tunnel = 1,936,917.295 m^3.
1,936,917.295 * 9480 * 1,000,000 = 1.836197596e16 j.
Pressure in the inner core is 330 to 360 GPa, we'll use the average.
2.9 + 0.028 * 345 = 12.56 GPa
The diameter of the inner core is 2440 km, so the volume of this part would be 1,042,823.963 m^3.
1,042,823.963 * 12560 * 1,000,000 = 1.309786898e16 j.
Total is 3.631826775e16 j, or 8.68027432 Mt.
I used a lot of really conservative estimates here too, so this is a major low-end. And he did it while weakened.