Originally posted by JBL
Sin, listen to me. You are right about taking on panel showings to use on a battle board, but the mistake people are making is this... They don't know how to separate what a Character can and really cannot do. So if Carver say that " the madder hulk gets, the stronger hulk gets" he can transfer that over from the comics to a battle board because that has been hulks power set for many years, so when hulk fights a stronger foe, hulk will eventually catch and surpass them and strength. Carver can use that in a better board. On the other side of the coin, Superman fights a stronger and more powerful foe that nearly kills him, YET by writers intent ignoring Superman's power set because his power set does not allow him to defeat that foe, THEY ALLOW the hero to win. You cannot transfer that over to a battle board. That goes for any hero. I go into more detail with you soon, but did you know that certain writers are planning a crossover that will put Superman up against Hulk and Thor? And DC admitted that Hulk was stronger than doomsday who is just as strong as Superman? Remember when Thor said another bout with the kryptonian will hold many surprises? Keep this statement in mindðŸ‘
You claim that Superman is supposed to lose to some villains when comics have him winning instead. Actually the opposite is true (Superman is supposed to beat nearly everyone in comics but writers have him job instead).
Here's proof. There are multiple examples of Superman possessing nanosecond up to femptosecond perception times and speed. So theoretically, he's supposed to statue all of his villains except Zoom. Now he has many planetary feats all the way up to million of stellar weight feats. If none of his villains can even lift a planet then theoretically they should be an insect to Superman.
So in reality, Superman is not just supposed to beat those beings but beat them in a way that they are nothing to him. Rather, writer's write him down in order for the villain to seem to have a chance. See you have it all wrong.