Namor (MCU) vs Homelander (The Boys)

Started by DarkSaint858 pages
Originally posted by h1a8
😄

Yup. I wanted to make clear what you were doing.

Originally posted by h1a8
Also, in this case, mass is directly proportion to surface area. Reducing the mass (exclude the windows) also reduces the surface area by the SAME FACTOR.

One more thing. Man made lasers have heated aluminum to over 3 million degrees. 20,000 degree Celsius is nothing compared to that. So I don't see how 20000 is overly optimistic. It's really a gross lowball estimate. I didn't even include the mass of the stringers and formers (which add significant more mass of aluminum).
He cut the plane at 60 degrees. That means the length of the cut is significantly bigger than the height of the plane. Again more mass.

The thickness of a plane's skin can be over 2 mm and about 1.4mm average for smaller planes. I used 1 mm. That's 40 percent less mass I used.

Lastly I assumed he just heated the aluminum to 660 (the beginning of being melted) when in reality it could have been heated to over 1000 degrees.

I took liberty to lowball every number instead of at least using averages.

Wut. I see you're doubling down on your error now, let me explain:

Mass is proportional to volume, not surface area, and it NEVER is unless you're having a uniform lamina. Which you're not. So it's not.

Originally posted by DarkSaint85
Yup. I wanted to make clear what you were doing.

Wut. I see you're doubling down on your error now, let me explain:

Mass is proportional to volume, not surface area, and it NEVER is unless you're having a uniform lamina. Which you're not. So it's not.

What error? I just proved using an all aluminum design is 100% valid in proving what the HV is capable of. Just because you don't understand the proof doesn't make it invalid. You accepted the proof. Now you trying to back track lol.

Also, I said, "in this case" surface area is proportional to the mass.
The shape of the cross section of the fuselage is approximately uniform.
Therefore any deviations will result in error in less than 5% error.
The MANY lowball assumptions does more to compensate for any small deviations.

Originally posted by h1a8
What error? I just proved using an all aluminum design is 100% valid in proving what the HV is capable of. Just because you don't understand the proof doesn't make it invalid. You accepted the proof. Now you trying to back track lol.

Also, I said, "in this case" surface area is proportional to the mass.
The shape of the cross section of the fuselage is approximately uniform.
Therefore any deviations will result in error in less than 5% error.
The MANY lowball assumptions does more to compensate for any small deviations.

Me repeating your assumption is not accepting it, you misunderstood. I am trapping you by making sure everyone can see clearly your wrong assumptions.

I know you said 'inthis case' - hence my use of the word Never.

Prove this 5% figure, now. Because you are again making wild leaps of assumptions, and no amount of pretty formatting is saving you lol.

Originally posted by DarkSaint85
Me repeating your assumption is not accepting it, you misunderstood. I am trapping you by making sure everyone can see clearly your wrong assumptions.

I know you said 'inthis case' - hence my use of the word Never.

Prove this 5% figure, now. Because you are again making wild leaps of assumptions, and no amount of pretty formatting is saving you lol.

Lack of understanding isn't a rebuttal. I've proven what the HV is capable of.

The fuselage shape is nearly circular. Additionally, the lowball numbers significantly compensate for the windows (using 40% less mass in one instance, ignoring the stringers and formers, not using 60 degrees to increase the length of the slice, etc.).

The goal was to prove it exceeded 20,000 degrees, but the calculation showed temperatures above 40,000 degrees—more than double the target. Adding the omitted mass likely raises it above 50,000 degrees.

If that isn't convincing, consider this final point: the window area is far less than half the volume. Therefore, removing less than half the mass still results in a temperature exceeding 20,000 degrees. Even using half the mass still yields a temperature above 20,000 degrees.