Originally posted by gogogadgetgo
@h1If you want to be technical about it
Reinforced concrete has a compressive strength of 20-30MPa. Say the Earth has a Compressive strength of 40MPa
Now, the lasso was tied around the earth multiple times, lets say that the total surface area covered by the lasso is 10% of the earths surface area.
Earths SA = 4 x Pi x r^2 = 4 x Pi x (6,370,000m)^2 = 5.100644719 E14 m^2
10% of that is 5.100644719 E13 m^2
Now multiplying surface area with the compressive capacity
5.100644719 E13 m^2 x 40 N/mm^2 x (1000mm)^2/(1m)^2 =
2.040257888E21 NConverting to tons
2.040257888E21 N x 1ton / 8896.44N = 2.29334193E17 tonsConverting to earth weights
2.29334193E17 tons x 1 earth weight / 6.58E21 tons
we arrive at 3.485322082E-5 earth weights
This value is the least amount of force needed to be exerted on the earth by the lasso to crush it into little tiny earth pieces.
Now since Superman, according to you was pulling more than 50 earth weights, then the earth should have shattered and crushed by the force exerted by Superman.
Base on this, Superman, Wonderwoman and MM should be exerting less than 2.29334193E17 tons of force to prevent the earth from crumbling to little pieces. Now thats about 0.0035% of the earths total weight.
In conclusion, Superman could only have been pulling at most 0.00116% of the earths weight.
See...I can be technical too
😈
That wasn't the feat I applied the greater than 50 Earth weights to. It was the Hal and Superman feat against Starbreaker. In the WW, Superman, and MM feat the calculation was less.
The lasso is magical and it's possible for Kyle and the lasso to stabilize the Earth when the pulling was done. But that's irrelevant since Force is proven through acceleration. You can't accelerate anything of mass without force. Doesn't matter if the object is supposed to be crushed or not.
Now on the other hand, if an object fails to accelerate then you can't prove that the force is greater than it's weight.
Originally posted by gogogadgetgo
Actually no, with my new calculations, I have arrive at a conclusion that Superman was only pulling 1.1618E-5 earth weights or just 0.001618 percent of the earths total weight.😆
Actually you didn't. F=ma proves the force is being applied. With your logic, Thor exerted even less force than Superman since he didn't even move the Earth at all.
Originally posted by h1a8
That wasn't the feat I applied the greater than 50 Earth weights to. It was the Hal and Superman feat against Starbreaker. In the WW, Superman, and MM feat the calculation was less.
Regardless as to which feat it was, applying 50 earth weights of force would destroy the earth.
Originally posted by h1a8
The lasso is magical and it's possible for Kyle and the lasso to stabilize the Earth when the pulling was done.
And what we have here is h1 double standards, He cant accept the lasso is Magical but cant accept that Thor's feat as magic in it too..
Regardless if you can stabilize the earth or not, exerting 50 earth weights would destroy it
Originally posted by h1a8
Force is proven through acceleration. You can't accelerate anything of mass without force. Doesn't matter if the object is supposed to be crushed or not.
It does matter if the earth is crushed, Applying even half an earth weight of force would destroy the earth and on panel, the earth was not destroyed, hence it is obvious that Superman/Kyle and Superman,Wonderwoman and MM were not even exerting half an earth weight of force.
F=ma we all know that but F=PA also or F=SA where in S is stress and A is surface area, or didn't you know that? hmmm... I bet you didn't
you may have theoretical physics to back you up but I have real world engineering backing me up. Real world application > theoretical computations
Also, again here we see h1's double standards, the earth didnt move hence Thor couldnt have possibly been appyling even 1 earth weight of force. But when I refuted your computations, you dismiss it. Exerting more that 10% of an earth weight of force would destroy the earth. So, since the earth was not destroyed , base on my computations Superman/kyle or SS,WW,MM are applying less thant .003% of an earth weight force.
Originally posted by h1a8
Now on the other hand, if an object fails to accelerate then you can't prove that the force is greater than it's weight.
Then how do you quantify the force that is applied when crushing rocks? Acceleration is stupidly slow but force is massive...
Again, F=ma isnt the only way of computing force.
This just shows how completely biased you are. Accepting DC feats as is without questioning it while dismissing Thor's feats as irrelevant just coz it shows Thor being at the same level of Superman
Face it, you lose. I win. My real world engineering just WTF kicked your theoretical physics' ass
😆
Originally posted by h1a8
Actually you didn't. F=ma proves the force is being applied. With your logic, Thor exerted even less force than Superman since he didn't even move the Earth at all.
But I ddint compute F=ma but computed it F=PA where P = pressure and A = surface area / cross sectional area.
Stop grasping at straws.
Face it, you have no counter for my awesome Thor 100 Earth weight feat so you try to just discredit it. bohohoho... poor h1, cant accept that some flaky random nut job like me just WTF trashed your "50 earth weight Superman feat"
Sucks to be you
😆
Got to go now and live life. But I'll be back to post more awesome quantified Thor feats that will trump every Superman feat you have.. if you have any that is. 😈 😆
Hat is the weight of an object on eart vs the weight of an object in space.
Supposedly in comparison to bein on the face of the planet a 1 ton or 2000 pound object in space is for the most part weightless...
Superman attempting to move an object in space with no resistance is not as difficult as being on the surface of the planet lifting an object up.
Thus. If you figure the Midgard serpent was at least 1 ton, and judging by its size it was the at least that... Thor would have lifted at Least 2000 pounds.
Superman lifting 50 earth weights in a weightless environment makes it 50 x 0= which is 0 pounds... Let's round up to 1 pound...
2000 vs 1... That's 2000 times as much weight.
Thus Thor is at least 2000 times stronger than superman.
Since in comics we rely on logic and faulty science per hia8...
Logically an object floating is space is weightless,
Thus my Thor is stronger than hia8's superman.
Originally posted by gogogadgetgoNot if it is stabilized in some kind of way.
Regardless as to which feat it was, applying 50 earth weights of force would destroy the earth.
We can accept that Thor's feat had magic in it. The point was that he didn't exert more than 1 Earth weight of force since the planet didn't move. There is no double standard here.
And what we have here is h1 double standards, He cant accept the lasso is Magical but cant accept that Thor's feat as magic in it too..Regardless if you can stabilize the earth or not, exerting 50 earth weights would destroy it
This is false since the Earth can be stabilized in some kind of way to prevent it from being destroyed. That is where the suspension of disbelief takes over.It does matter if the earth is crushed, Applying even half an earth weight of force would destroy the earth and on panel, the earth was not destroyed, hence it is obvious that Superman/Kyle and Superman,Wonderwoman and MM were not even exerting half an earth weight of force.
I repeat, the suspension of disbelief allows us to say that the Earth was stabilized to prevent it's destruction. We have evidence of this since Hal, a GL, can put himself in a field and accelerate to light speeds instantly. Without stabilization, the G forces would kill Hal.F=ma we all know that but F=PA also or F=SA where in S is stress and A is surface area, or didn't you know that? hmmm... I bet you didn't
you may have theoretical physics to back you up but I have real world engineering backing me up. Real world application > theoretical computations
Also, again here we see h1's double standards, the earth didnt move hence Thor couldnt have possibly been appyling even 1 earth weight of force. But when I refuted your computations, you dismiss it. Exerting more that 10% of an earth weight of force would destroy the earth. So, since the earth was not destroyed , base on my computations Superman/kyle or SS,WW,MM are applying less thant .003% of an earth weight force.
You don't get it. The fact that the Earth didn't move implies that to break the grip was less than 1 Earth weight of force. AlsoThen how do you quantify the force that is applied when crushing rocks? Acceleration is stupidly slow but force is massive...
Again, F=ma isnt the only way of computing force.
This just shows how completely biased you are. Accepting DC feats as is without questioning it while dismissing Thor's feats as irrelevant just coz it shows Thor being at the same level of Superman
Face it, you lose. I win. My real world engineering just WTF kicked your theoretical physics' ass
😆
2. Also, you are forgetting that it was more of a magical crushing, since the Serpent was intangible to everything on Earth and thus to break the grip could be done by simply overpowering the Serpent's durability of it's head attached to it's body. Remember, my toe scenario?
But you are right, F=ma isn't the only way to calculate force but it is the definition of force and should trump, in weight, anything else.
Originally posted by rotiart
Hat is the weight of an object on eart vs the weight of an object in space.
Supposedly in comparison to bein on the face of the planet a 1 ton or 2000 pound object in space is for the most part weightless...Superman attempting to move an object in space with no resistance is not as difficult as being on the surface of the planet lifting an object up.
Thus. If you figure the Midgard serpent was at least 1 ton, and judging by its size it was the at least that... Thor would have lifted at Least 2000 pounds.
Superman lifting 50 earth weights in a weightless environment makes it 50 x 0= which is 0 pounds... Let's round up to 1 pound...
2000 vs 1... That's 2000 times as much weight.
Thus Thor is at least 2000 times stronger than superman.
Since in comics we rely on logic and faulty science per hia8...
Logically an object floating is space is weightless,
Thus my Thor is stronger than hia8's superman.
You don't understand F=ma. It has nothing to do with weight.
If a bowling ball has a mass of 5kg and you accelerated it in space at 9.81m/s^2 then this is equivalent to lifting the bowling ball while being on the surface of the Earth. If you accelerated it by 19.62m/s^2 then this is equivalent to lifting a 10kg object on the surface of the Earth. The more the force then the greater the acceleration you can apply to an object in space. In space, you will be able to accelerate a tank, but very slowly since your force is small (you have human strength). You will be able to accelerate the tank far less than 9.81m/s^2. Now if you are able to push accelerate the tank at 9.81m/s^2 then you most definitely can lift it while being on the Earth.
lol @ hi1 grasping at straws
Stabilizing earth in someway? really? thats all you can come up with? You claim that the earth wont be destroyed if its "stabilized in someway" and yet cant accept the fact that the earth didn't move when Thor tugged on the Serpent due to the nature of the Serpent.
Plus, where is this proof of stabilization? Clearly on panel, all we see is a lasso tied around the earth and a green lantern construct anchored on the earth. do we see some magical shield or green lantern shield? nope! there is none! hence, it was not stabilized in anyway and the Earth should have been destroyed to the force your are claiming that Superman exerted.
Yet, the Earth didn't get destroyed. This proves that all your claims of 50 earth weights is false.
Unless you can show on panel proof of this stabilization you're claiming, Superman didn't exert 50 earth weights of force and Thor is exponentially stronger Than Superman as I have proven that Thor has exerted over 100 earth weights of force while Superman could barely exert 0.003% earth weight of force.
Thor >>>>>>>>>>>>>>>>>>>>>>>>>>> Superman in strenght
Now that we now that Thor is exponentially stronger than Superman, all superman has now is his speed.
Hence in any fight Thor wins 10/10 against Superman.
Originally posted by h1a8
You don't understand F=ma. It has nothing to do with weight.
If a bowling ball has a mass of 5kg and you accelerated it in space at 9.81m/s^2 then this is equivalent to lifting the bowling ball while being on the surface of the Earth. If you accelerated it by 19.62m/s^2 then this is equivalent to lifting a 10kg object on the surface of the Earth. The more the force then the greater the acceleration you can apply to an object in space. In space, you will be able to accelerate a tank, but very slowly since your force is small (you have human strength). You will be able to accelerate the tank far less than 9.81m/s^2. Now if you are able to push accelerate the tank at 9.81m/s^2 then you most definitely can lift it while being on the Earth.
F=ma?
Force exerted is equal to the mass of an object multiples by the rate of its acceleration.
And it has everything to do with it because the rate necessary to lift an object from opposing force such as acceleration gives you valuations for things like escape velocity.
And you haven't considered things like TFT at all considering there is no escape velocity consideration in space but there is for lifting an object on earth
Like the comparison of lifting an object on earth vs on Pluto. The force necessary to move the object is figured by knowing its mass by it's rate of acceleration.
Your entire post is a fail.
And before yu say something as stupid again as not understanding f=ma.
Realize that that we need to know change in velocity over change in time...
Explain wtf that has to do with moving a planet.
Let me simplify this for your little brain.
A rocket leaving earth requires more more force to leave the earth than moving that same object floating in space.
And if you've ever done these calculations like I did back when I was in physics you'd know wth I'm talking about instead of what bill nye the science guy told you on public access.
Re: Thor vs Superman (Pure strength)
Originally posted by PillarofOsirisIn feats I would think superman would. (mostly assuming this because I keep finding more of the insane shit he's done in the past) But I actually don't know his best straight up lifting feat. In lifting Thor's yanking the Midgard Serpent off the Earth. I'd like to know Supermans...
Who can lift more over their head? Who has the single best strength feat?
Can someone show some pure strength fts. We don't know how much strength it took to be an engine to the Wheel of Mag, we don't know how much strength was required to move the yggdrasil...not pure strength fts if you ask me. Pushing a planet requires more than strength. Flight, durability, and speed is also included.
Whats the best lifting ft each have? Has any of them lifted a mountain, has any of them lifted a city over their head. What does each combatant bring to the table regarding pure strength fts.
Originally posted by abhilegend
^Its an abstract strength feat though, like infinite book and slowing spectre or lifting sky. Despite what some would think, I don't think that the midgard serpent was anywhere close to being as heavy as earth.
I dont think the midgard serpent is as heavy as the earth either. But it is one huge ass serpent said to be able to coil itself around the earth multiple times. If were to believe the on panel representation, it can coil its body around the earth at least twice, which makes it one huge ass snake.
IMO, when characters starts lifting content size piece of rocks, busting moons and planets, and pulling planets, the feat becomes more ridiculous than impressive.
Lifting a car is impressive, lifting a tank is damn impressive, supporting an entire skyscrapers weight is really damn impressive, busting a mountain is kinda silly, busting a moon size rock is stupid and pulling a small planetoid is just down right ridiculous.