The Key would be highly unstable against phase transition. Dwarf star matter can only exist as dwarf star matter (technically, this is electron-degenerate matter) within the enormous gravitational field of a dwarf star. Remove a key-sized chunk of it and bring it to a 1-atm environment, and it would explosively return back to "normal" state of matter. I don't know which mechanism is keeping the Key stable but I'm sure if Superman threw it at someone at full strength, this mechanism would fail, triggering the phase transition.
Some physics follows.
We aim to calculate the electron-degeneracy pressure active within the Key. Electrons are fermions and obey the Pauli exclusion principle: when matter is compressed into dwarf-star densities, its electrons experience a repulsive quantum effect, which then produces an extremely high pressure. It is, in fact, this pressure that prevents a white dwarf star from collapsing further into a neutron star or black hole.
In a dwarf star, gravity and electron-degeneracy pressure are in balance. But in a key-sized piece of dwarf star material, self-gravity is insignificant next to this pressure (I can show the math, upon request), so that as soon as the "mystery mechanism" I referred to above fails, the key will detonate with extreme violence.
The electron degeneracy pressure P_e is given by:
Here, h_bar is the reduced Planck's constant and m_e the electron mass, which are well-known physical constants. In order to calculate P_e, we thus need electron number density ρ_e within the key. The mass of the key is 4.5E8 kg, which means that it contains approximately 2.7E35 nucleons. There are approximately 2 nucleons for each electron in dwarf star material, yielding 1.35E35 electrons in this case. The volume of the key is about 1E-6 m^3. Thus
ρ_e = 1.35E41 electrons / cubic meter.
Plugging this in the expression for P_e yields:
P_e = 8.3E30 pascals.
This is a truly ridiculous outward pressure. Assuming the surface area of the Key is 6E-4 m^2, this corresponds to an outward force of 5E27 newtons. This is equivalent to the weight of 5E26 kilograms under standard gravity, i.e. the weight of approximately 80 Earths.
So, once the Key has penetrated its hapless target, it likely detonates with the force equal to the weight of 80 Earths. This would erase every single being on the OP's list.
FURTHER READING:
https://en.wikipedia.org/wiki/Degenerate_matter
https://en.wikipedia.org/wiki/Electron_degeneracy_pressure
https://en.wikipedia.org/wiki/Pauli_exclusion_principle
https://en.wikipedia.org/wiki/Nucleon