War and Link vs Kratos, Bayonetta and Dante

Started by BloodRain60 pages

Energy (joule) = ½ mass (in kg) x velocity2 (in meters per second) 😐

Dantes strength based on Saviours pressure on his body:

kilograms: 900 000

Velocity 70= 4900 squared

velocity squared times 900k kilograms divided by 0.5 gives following:

Joules: 2205000000

Divided by the 1.3 blah blah number for pouund per foot. This gives

1626324539 PSI per square foot, divide by 144 for square inches:

11293920 inches squared of force.

Divided by 22 (dantes combined palms area)

513360 pounds of force against Dante, AKA 232 tonnes?

In short, mass (900k) x velocity2 (70x70=4900) halved and then divided by pound per foot, then by 144 for inch, then by the surface area.....

Scream also gave a calculation for something like a swords edge. But this is irrelvent here as Saviours hand is blunt.

kilograms: 900 000 [thats about half of the weight.]

1626324539 PSI per square foot, divide by 144 for square inches:

Divided by 22 (dantes combined palms area) [dividing by 144 was the combined palm area, you did this twice]

The weight of his arm was 900 tonnes? 900k kilograms? I ignored the odd tonnage for those horns on his wrists.

The 144 turns square feet into square inches yes? but thats only the base for a square inch, you still need to divde by how much this force is spread across Dante, e.g. 22?

So its # PSI per foot divided by 144 to get # per square inch, this has ot be divided again by the area this force is spread over hm?

Soz for double post, but I used the 2000 tonnes this time for Saviours arm. Assuming your numbers are correct, my numbers come to:

Revised NUMBERS!

Kilograms: 2 000 000

Velocity 70= 4900 squared

velocity squared times 2 million kilograms times by 0.5 gives following:

Joules: 4900000000

Divided by the 1.3 blah blah number for pound per foot. This gives:

3614054531 PSI per square foot, divide by 144 for square inches: 25097601

Divided by 22 for Dantes palms= 1140800 pounds of force, AKA 517 tonnes

Remember the last bit would have to be done since afterall, Dantes handes are not one inch squared in size or area, hence why the overall energy has to be released across the palms like smoothe ointment over a sore.

So all in all, Dante can survive 512 tonnes of PSI, this would be multiplied by a sharper edge therefore he is hardly immune to stabbing.

I still think we need to take into account the sword Dante uses (rough area estimated at 240), thats what the fist strikes so therefore the pressure preads over the swords area first....wouldnt we get square inch of Saviours impact divided by the swords which is then divided by Dantes hands, by then Dante may not be getting much PSI at all? not sure how it works when concerning objects taking some abosorbtion.

''So its # PSI per foot divided by 144 to get # per square inch'' this is where you stop thats the psi.

The same psi is transferred through the sword to his hands, all the energy had to go somewhere.

Thats for the PSI for one square inch though right? if Dantes hands were that small then yes we would stop but we have to divide the energy by the surface area of Dantes hands to get the PSi, energy does not stop at one square inch on impact.

I agree, therefore Dante is hit by about 45 tonnes of PSI which is fairly impressive still by the time the sword has taken the impact. Surprising durability though considering the sword is so strong. Thing is, I think this calculation may have problems with indestructable objects. Surely an indestructable object with an enormous surface area could absorb most of the tonnes of even really strong attacks?

ScreamPaste:
Link in OoT threw a granite block weighing 1388.994 tons at a speed of over 75 meters per second, with relative ease. For this exercise, I'll be rounding these numbers down to 1300 and 75.

To accellerate a block that heavy to that speed Link had to generate 3316894205 joules of energy. Ganon is stronger than even OoT Link with the gauntlets, and TP Link sword locked with Ganon. [AHAH, relevance!]

This is; 2446415618 foot-pounds of force, now divide by the area of his hands. let's assume for the pure lulz that the palms of his hands combine into a square foot of area. Divide by 144 for PSI and you get 16988997 from just his own down-rounded strength, spread over an impossibly large surface area, and this amount of force did no harm whatsoever to Link.
FYI, thats 8494 tons of PSI

I based Dante's off this, your site and several other formula's. The extra /22 is not needed, thats like saying ^ 16988997/22 = 772227. Giving Link 386 tons of psi.

/144 gives the psi.

What your doing is flawed because your taking the amount of pounds/inch and saying thats how much effects the whole of Dante, when thats the measurement for only 1 inch, you have to divide it by the surface area otherwise its like your saying the energy just disapates as soon as it hits 1 square inch of Dantes hand , can you not see the logic in spreading an amount of pressure over the area its striking? 😐

I see your using Screampaste evidence?! well I have moar! the bolded areas are important, the blue bits are the things your ignoring.


ScreamPaste wrote on Feb 2nd, 2010 11:01 PM:
I think I may have missed a step in teaching you. To convert foot pounds into pounds/inches, you need to divide by 144, and then divide again by the surface area.


ScreamPaste wrote on Feb 2nd, 2010 09:04 PM:
Not a problem, sir. 😮 Now that we're being civil with one another I take no issue with spreading my mathematical AIDS 😛

PSI is the result of pound-foot force on a single inch of surface area, and a pound foot of force is equal to 1.3558179483314004 joules.

PSI = pounds per square inch or pressure per square inch, if another unit of weight measurement is used. So, in order to measure PSI, we first need the energy output of a character's strength in joules. If you can get me that, the rest is pretty easy.

Convert the joules to pound foot force by dividing the number of jouled by 1.3558179483314004, then convert pound/foot into pounds/inches and divide by the surface area of the strike. So, let's use the example of a punch. If I punch with 1.3558179483314004joules of force (Actual measurement may vary!), then that's one foot pound, divided over let's say.. 8 square inches. (not 8 inches squared, which would turn out a total of 64 inches!). divide that one foot-pound by 8, and that's my PSI for a punch.

Also to counter your Screampaste info, whats happening is different. Dante is blocking force with his hands wheras link is blocking it through something isnt he? its not the same as the Saviour punching down on you. Also his math is flawed, mainly because assuming Ganon is just as strong because another link just so happens to be yadda yadda etc is not a good justifaction for strength, personally I dont buy link being that strong anyway but assuming I did, I still wouldnt buy Ganon is that strong based on swordlocking with a guy.

Originally posted by BloodRain

/144 gives the psi.

For the love of my greasy grubby brown stained white pants yes! but NOT taking into account surface area.

Hangabout, your screampaste info does indeed mention dividing by surface area....he just did not mention the exact number of surface area. (well he did but did not show the workings and confused us by spacing out his transformotion of feet to inches).

Originally posted by BloodRain
ScreamPaste:
Divide by 144 for PSI and you get 16988997 from just his own down-rounded strength, spread over an impossibly large surface area, .

Maybe it just the way he said it and he did indeed math this wrong..the equation he told me above makes more sense than using the pound/inch force for just one inch, when the surface area is larger.

I already corrected that error, BT 😛 I was all over the place doing different math in different windows when our PM's innitiated, and I made a mistake early on.

You do need to determine the area that the force is being spread over, though, because the Pound-foot formula assumes a square foot.

Saved myself some effort in the original example by assuming Link's hand was that size. (IMPOSSIBLEY LARGE D: ) This would mean the force is spread out mor,e shrinking the pressure.

Please show me the error and then the correction, I am confuseded!

That makes sense, you do not have forces of energy that do not spread when impacting.....I may be new to PSI, but I still know it doesnt make sense for energy to just strike and disapear...

Like I said in PMs, I'm a TERRIBLE teacher! So, I apologise.

and divide by the surface area of the strike. So, let's use the example of a punch. If I punch with 1.3558179483314004joules of force (Actual measurement may vary!), then that's one foot pound, divided over let's say.. 8 square inches. (not 8 inches squared, which would turn out a total of 64 inches!). divide that one foot-pound by 8, and that's my PSI for a punch.
This was my error.

8 square inches is actually 8/144 of a foot pound. or, one 18th.So, you'd divide by one eighteenth.

Thats only because you did not calculate PSI, you were calculating a square foot of force. You also forget to tell me how to turn feet of force into inches, but you corrected that later as well.

So now its Foot of force/144 to make inches of force/surface area=pressure on the area?

Pretty much, yes. 😛

Thats what I have been doing? its calculated that Dantes hands of 22 inches squared were the surface area, so I divided my number for inches/force by that surface area?

Well, I have not slept. So, I call tired johns. I just wanted to clarify that I did make an error, and endeavored to correct it. 😛

Damn you! settle our argumet godammits! you owe me this as I did win the funny animals contest 🐰

Geez you pass out for 10mins and all the answers change @__@

So i was right about it stopping at 144? Bloody huge hands lol

lol no he outlined how he divided the square inches which you get by divided by 144 by the square foot which he took for Links hand. So in this case were not dividing by a square foot, were diving by 22 inches because thats Dantes hands surface area. Although I think we should be diviing by 240, because thats the swords surface area.

Also is there a way I can run the timing of a youtube video in milliseconds?